by elimination,substitution or through the matrix method.
how do you use the substitution method for this problem 2x-3y=-2 4x+y=24
That's exactly the purpose of the substitution method ... to get an equation with one less variable. When you have it, you solve it for the variable that's left.
There are no disadvantages. There are three main ways to solve linear equations which are: substitution, graphing, and elimination. The method that is most appropriate can be found by looking at the equation.
Substitution method: from first equation y = 5x - 8. In the second equation this gives 25x - 5(5x - 8) = 32 ie 25x - 25x + 40 = 32 ie 40 = 32 which is not possible, so the system has no solution. Multiplication method: first equation times 5 gives 25x - 5y = 40, but second equation gives 32 as the value of the identical expression. No solution.
This is not Calculus.y=7(Already solved)substiute y=7 into y=8xtherefore 7 = 8xtherefore x = 7/8
The substitution method undoes the chain rule.
From first equation, -y = 3x + 3. Substitute in second equation: -3x + 5(3x + 3) = -21 ie 12x = -36 so x = -3 and y = -(-9 + 3) = 6. Easier method: subtract first equation from second giving -4y = -24 so y = 6, this in first equation gives -6 = 3x + 3, ie 3x = -9 so x = -3
y = x - 7 x + y = 5 Substituting for y in the second equation, x + (x - 7) = 5 or 2x = 12 so that x = 6 Then, from the first equation, y = 6 - 7 = -1 So, (x, y) = (6, -1)
From first equation: y = 2x - 5Substitute this in second equation: 3(2x - 5) - x = 5, ie 6x - 15 - x = 5ie 5x = 5 + 15 so x = 4 and y = 3
If the process of substituting leads to an identity rather than an equation then the system has infinitely many solutions.
If: x+y = 4 and y = 2x+1 Then: 4-x = 2x+1 => 3 = 3x => 1 = x So by substitution: x = 1 and y = 3
y = 17 + 2x from second equation, substitute in first equation: 2x + 6(17 + 2x) = -10 ie 2x + 102 + 12x = -10 ie 14x = -112 so x= -8 and -16 + 6y = -10 ie 6y = -10 +16 so y = 1 Other method: Add the two equations, giving 7y = 7 so y =1 and x = -8
Solution can be found by using three methods: 1. Cross Multiplication Method 2. Substitution Method 3. Elimination Method Other Method can also be there but I don't know You can further get info about these method by searching these on Google Search.
Substitution method: y = 1 + x so 2x + (1 + x) = 4, ie 3x = 3 so x = 1 and y = 2
G-Given U-Unknown E-Equation S-Substitution S-Solve