Best Answer

-3x + 40 = 38

Subtract 40 from both sides: -3x = -2

Multiply both sides by -1: 3x = 2

Divide both sides by 3: x = 2/3

Q: -3x plus 40 equals 38

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y=16 x= -4

2x+9 = 49-3x 2x+3x = 49-9 5x = 40 x = 8

3x-5=40x+3 Subtract 3x-5 from each side 0=37x+8 -8=37x x= -8/37

7x-40 = -3x Add 40 and add 3x to both sides:- 7x-40+40+3x = 3x-3x+40 10x = 40 Divide both sides by 10:- x = 4

7. 8x-40=2x+2 4x-20=1x+1 3x-21=0 3x=21 therefore x=7

Related questions

4x + 10 + 3x = 40 - 3x 4x + 10 + 3x + 3x = 40 20x = 40 x = 2

3x + 2x = 40 5x = 40 x = 8

x + 3x = 40 4x = 40 x = 10.

5

10 - 3x = x - 2x + 40 10 - 3x = - x + 40 10 - 40 = 3x - x -30 = 2x -15 = x

y=16 x= -4

2x+9 = 49-3x 2x+3x = 49-9 5x = 40 x = 8

x+30 = 3x-50 x-3x = -50-30 -2x = -80 x = 40

7x-4 = 3x+36Add 4, it cancels out.. So,7x = 3x+40Now subtract 3x from 7x..4x = 40..40 divided by 4 is 10So, X= 10

3x-5=40x+3 Subtract 3x-5 from each side 0=37x+8 -8=37x x= -8/37

7x-40 = -3x Add 40 and add 3x to both sides:- 7x-40+40+3x = 3x-3x+40 10x = 40 Divide both sides by 10:- x = 4

7. 8x-40=2x+2 4x-20=1x+1 3x-21=0 3x=21 therefore x=7