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10 plus E in a D?

Updated: 4/28/2022
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It could be a Ditloid, 10 Events in a Decathlon.

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A plus b plus c plus d plus e equals 30 where c plus e equals 14 and d equals b plus 1 and a equals 2b-1 and a plus c equals 10 find values of letters?

a+b+c+d+e = 30 (i) c+e = 14 (ii) d+b = 1 (iii) a = 2b-1 (iv) a+c = 10 (v) By (i)-(ii)-(iii): a = 15 then, by (iv): b = 8 and by (v): c = -5 Also, b = 8 so by (iii): d = -7 and then by (i), e = 19


If a plus b equals c and b plus c equals d and c plus d equals e and a equals 7 and e equals 5 what is a plus b plus c plus d plus e equal?

the answer is a


A plus B plus C plus D plus E?

the correct answer is the 15 number in the alphabet which is o


What five numbers have a median of 12 a mode of 10 and mean of 12?

Assuming by "numbers" you mean "whole numbers":{10, 10, 12, 13, 15}If the five numbers are {a, b, c, d, e} with a &le; b &le; c &le; d &le; e, then:median = 12 &rarr; c = 12leaving only two numbers (a, b) &le; 12.mode = 10 &rarr; two or more numbers equal 10 (which is less than 12) &rarr; a = b = 10The final two numbers (d, e) are not equal, both greater than 12, and such that the sum of all five numbers is 60.10 + 10 + 12 + d + e = 60 &rarr; d + e = 28 &rarr; d = 13, e = 15&rarr; {a, b, c, d, e} = {10, 10, 12, 13, 15}[If "numbers" includes "decimal numbers" (ie numbers with a fractional part), then as long as d + e = 28 and 12 < d < e there are infinitely many solutions, eg {10, 10, 12, 12.5, 15.5}, {10, 10, 12, 13.75, 14.25}]


Ax5 plus bx5 plus cx5 plus dx5 plus ex5 equals abcde what is abcde?

a(x5) + b(x5) + c(x5) + d(x5) + e(x5) = abcde(a+b+c+d+e) x5 = abcdeThis equation has at least 5 variables. To solve for all of them requires at least 4 more equations.

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If a plus b equals e what is e plus d?

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A plus b plus c plus d plus e equals 30 where c plus e equals 14 and d equals b plus 1 and a equals 2b-1 and a plus c equals 10 find values of letters?

a+b+c+d+e = 30 (i) c+e = 14 (ii) d+b = 1 (iii) a = 2b-1 (iv) a+c = 10 (v) By (i)-(ii)-(iii): a = 15 then, by (iv): b = 8 and by (v): c = -5 Also, b = 8 so by (iii): d = -7 and then by (i), e = 19


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If a plus b equals c and b plus c equals d and c plus d equals e and a equals 7 and e equals 5 what is a plus b plus c plus d plus e equal?

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Let x = abc be a 3-digit number. The expanded for of x is 100*a + 10*b + c.And let y = de = 10*d + e be a 2-digit number. Then x*y = 1000*a*d + 100*a*e + 100*b*d + 10*b*e + 10*c*d + c*e = 1000*a*d + 100*(a*e + b*d) + 10*(b*e + c*d) + c*e.


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A plus B plus C plus D plus E?

the correct answer is the 15 number in the alphabet which is o


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What does 10 D in a D S mean?

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What five numbers have a median of 12 a mode of 10 and mean of 12?

Assuming by "numbers" you mean "whole numbers":{10, 10, 12, 13, 15}If the five numbers are {a, b, c, d, e} with a &le; b &le; c &le; d &le; e, then:median = 12 &rarr; c = 12leaving only two numbers (a, b) &le; 12.mode = 10 &rarr; two or more numbers equal 10 (which is less than 12) &rarr; a = b = 10The final two numbers (d, e) are not equal, both greater than 12, and such that the sum of all five numbers is 60.10 + 10 + 12 + d + e = 60 &rarr; d + e = 28 &rarr; d = 13, e = 15&rarr; {a, b, c, d, e} = {10, 10, 12, 13, 15}[If "numbers" includes "decimal numbers" (ie numbers with a fractional part), then as long as d + e = 28 and 12 < d < e there are infinitely many solutions, eg {10, 10, 12, 12.5, 15.5}, {10, 10, 12, 13.75, 14.25}]


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