The diagonal of a 12' x 24' rectangle is approx 26.8'.
Use Pythagoras' therorem to find the diagonal of the rectangle which is 12 times the sq rt of 13
Use Pythagoras' theorem: 33.9411255 or about 34 feet
46.648 ft
radius = 24/2 = 12 units of measurement
Diagonal = square root of (24 squared + 26 squared) and that is square root of (576 + 676) and that is square root of (1252) and that is 35.38 feet
Use Pythagoras' therorem to find the diagonal of the rectangle which is 12 times the sq rt of 13
Diagonal = 36.9 feet
36.8782 ft
Use Pythagoras' theorem: 33.9411255 or about 34 feet
46.648 ft
There is no such square with the given dimensions but if you mean the diagonal of a rectangle then by using Pythagoras' theorem it works out as 8 times the square root of 13
radius = 24/2 = 12 units of measurement
The answer will depend on WHAT is 24 inches: the side, the diagonal, some other aspect.The answer will depend on WHAT is 24 inches: the side, the diagonal, some other aspect.The answer will depend on WHAT is 24 inches: the side, the diagonal, some other aspect.The answer will depend on WHAT is 24 inches: the side, the diagonal, some other aspect.
12" on either wall in a corner - easily.
The diagonal is 33.941 units.
FG should be 12.2²-12²(half of 24)=4.84 then square root it which equals 2.2 and then you double it so the answer is 4.4
sqrt(1152)