It is increasing by odd numbers consecutively.
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or: n = the term number, the rule is: n2 or n(n). 12=1(1x1=1), 22=4(2x2=4), 32=9(3x3=9), and so on.
2
So you're adding 3, 5, 7, 9, 11 etc 1, 4, 9, 16, 25, 36, 49
If inclusive, they are 1, 4, 9, 16, 25 and 36; if exclusive, they are 4, 9, 16, 25 and 36.
4,9,16,25,36,49,64,81,100,121
2(x2=) 4 3(x3=) 9 4(x4=)16 the next numbers are 16 5 25 6 36
They are: 25 and 36
t(n) = n2
Yes.
Yes
no it is not a recursive pattern because it isn't equal numbers.
-16
add 3,5,7,9and then to 25 add 11, adding odd numbers onto the last . 1+3=4, 4+5=9, 9+7=16, 16+9=25, 25+11=36 and so on
The perfect squares in the range are 25, 36 and 49.
The pattern is the squared numbers with the digits reversed. 92 = 81 → 18 82 = 64 → 46 72 = 49 → 94 62 = 36 → 63 52 = 25 → 52 42 = 16 → 61
These are the square numbers: 1, 4, 9, 16, 25, 36, 49, 64, 81...
assuming you mis-typed the 15 and instead it should be a 25, these are simply the squares of the number's position in the line. 12 = 1 22 = 2 32 = 9 42 = 16 52 = 25 (assume is what you meant) 62 = 36 You can also think of it as adding on the next in a series of odd numbers 1+3 = 4 4+5 = 9 9+7 = 16 which results from expanding (x+1)2 - x2 anyway
1, 4, 9, 16, 25, 36
1, 4, 9, 16, 25, 36