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Q: 1 510 plus 34

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510 is actually evenly divisible by 1, 2, 3, 5, 6, 10, 15, 17, 30, 34, 51, 85, 102, 170, 255, and 510.

100!

The factors of 510 are: 1 2 3 5 6 10 15 17 30 34 51 85 102 170 255 510 The prime factors are: 2 3 5 17

The general factors of 510 are :- 510, 255, 170, 102, 85, 51, 34, 30, 17, 15, 10, 6, 5, 3, 2, and 1 The prime factors are :- 2, 3, 5 and 17

0.5 + 1 + 0.75 + 2.125 + 0.5 = 4.875 = 4 and 7/8

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34034 = 510 x 66 + 374 510 = 374 X 1 + 136 374 = 136 X 3 + 102 136 = 102 X 1 + 34 102 = 34 X 3.......THUS 34 IS THE HCF OF 34034 AND 510.

You would multiply 510 by 1.2 to get your answer. The idea is: 510 plus twenty percent of 510 would be 1 X 510 + .2 X 510. Factoring out the 510 from each of these terms you get 510 (1 + .2)

510 X 1 = 510 Also, 2 X 255 = 510, and 5 X 102 = 510, and 10 X 51 = 510, and 6 X 85 = 510, and 15 X 34 = 510 The factors of 510 are: 1 X 2 X 3 X 5 X 17

34 + 1 = 35

510 is divisible by these numbers: 1, 2, 3, 5, 6, 10, 15, 17, 30, 34, 51, 85, 102, 170, 255, 510.

510 has these factors: 1, 2, 3, 5, 6, 10, 15, 17, 30, 34, 51, 85, 102, 170, 255, 510.

The factors of 510 are 1, 2, 3, 5, 6, 10, 15, 17, 30, 34, 51, 85, 102, 170, 255, and 510.The factor pairs of 510 are 1 x 510, 2 x 255, 3 x 170, 5 x 102, 6 x 85, 10 x 51, 15 x 34, and 17 x 30.

1, 2, 3, 5, 6, 10, 15, 17, 30, 34, 51, 85, 102, 170, 255, 510.

510 is actually evenly divisible by 1, 2, 3, 5, 6, 10, 15, 17, 30, 34, 51, 85, 102, 170, 255, and 510.

1, 2, 3, 5, 6, 10, 15, 17, 30, 34, 51, 85, 102, 170, 255, 510.

1, 2, 3, 5, 6, 10, 15, 17, 30, 34, 51, 85, 102, 170, 255, 510.

3-cubed plus 2 plus 1 plus 4= 34