To be divisible by 5, the last digit must be 0 or 5. The last digit of 28 is neither 0 nor 5, so it is not divisible by 5.
Yes - 252/9 = 28
3500/42 give 83 quotient,14 remainder next possibility 42*84 =3528. 28 must be added to 3500 then only it will divisible by 42.now check the dividend 3528 with the following divisor 49,56,63 3528/49=72 divisible 3528/56=63 divisible 3528/63=56 divisible So 3528 is divisible by 42,49,63,56 So 28 must be added 28 is the
56 is divisible by 1, 2, 4, 7, 8, 14, 28, and 56.
No - every other multiple of 4 is 4 12 20 28 etc are divisible by 4 but not by 8
28 is not divisible by 3.
28 is divisible by 1, 2, 4, 7, 14, 28.
28 is divisible by: 1, 2, 4, 7, 14, 28.
28 and its multiples.
The numbers that are divisible by 28 are infinite. The first four are: 28, 56, 84, 112 . . .
28, 56, 84, and all other multiples of 28 that are factors of other numbers are also divisible by 28.
evenly divisible 28 times
yes 4x7=28
No.
28 is a composite number as it is divisible by numbers other than itself and one. 28 is divisible by 1, 2, 4, 7, 14 and 28
No. 28 is not evenly divisible by 71.
Because 28/4 = 7