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2 plus 5i plus 6 plus 3i?

Updated: 9/16/2023
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14y ago

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I assume that "I" is a variable

2+5i+6+3i
7i+6+3i
10i+6
16i is the answer

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14y ago
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Q: 2 plus 5i plus 6 plus 3i?
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8 plus 6i-2 plus 3i?

(8+6i)-(2+3i)=6+3i 8+6i-2+3i=6+9i


P and q are complex number's where p equals 2 plus 5i and q equals 6 minus i - find pq?

p = (2 + 5i)q = (6 - i)pq = (2 + 5i) (6 - i)pq = 12 + 30i - 2i - 5i2pq = 12 + 28i + 5pq = 17 + 28iIts the same as multiplying polynomials. Just multiply all the combinations of terms, group, and simplify.


What is the complex conjugate -6-5i?

6+5i


Where do the parentheses go in this problem 12 plus negative 6 divided by negative five plus 2?

it would go inbetwwen 12 and negative 5i hoped this helped u /\__/\( + + )| |-----------\| \( )---------( )\ \| | | | \ \___/__| /__| \--------/\|Kitty


What plus what is -6?

Choose ANY number, for example, 5, -100, square root of 2, pi, or (5 + 3i). Subtract -6 minus your number, to get the other number.


What two numbers multiply to 45 and add to 12?

57


How do you factor and equation 2X2-6X plus 9?

The best way to factor this is to use the quadratic equation. Using an equation of the form: ax2 + bx + c = 0 You use the quadratic formula like this: x = [-b +(or -) sqrt(b2-4ac)]/2a For your problem, a = 2, b = -6, and c = 9. Therefore: x = [6 +(or -) sqrt(36 - 4(2)(9))]/4 = [6 +(or -) sqrt(36-72)]/4 = [6 +(or -) sqrt(-36)]/4 = (6 +(or -)6i)/4 = 3/2 +(or -)3i/2 Therefore the factorization is (x - 3/2 - 3i/2)(x - 3/2 + 3i/2).


What is the magnitude of -1 - 5i?

-6


What is the conjugate of 6-5i?

The idea here is to change the sign before the imaginary term. In this case, since there is a minus, you change it to a plus.


What is 6 plus 6 plus 6 plus 2 plus 6 plus 3 plus 6 plus 2 plus 8 plus 6 plus 6 plus 3 plus 6 plus 2 plus 3 plus 6 plus 6 plus 2 plus 2 plus 2 plus 6 plus 6 plus 6 plus 5 plus 6 plus 6 plus 6 plus 2 p?

132


How do you do the math problem (4-3i)(5 2i)?

To multiply complex numbers you can use the same FOIL rule that you use for multiplying binomials (First, Inside, Outside, Last).(4 - 3i)(5 + 2i) = (4)(5) +(4)(2i) - (3i)(5) - (3i)(2i) = 20 + 8i-15i - 6(i)^2= 20 -7i - 6(-1) = 20 + 6 -7i = 26 -7i.


What is 2 plus 2 plus 6 plus 6 plus 6 plus 6 plus 6 plus 6 plus 6?

46