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If x is the age of the son, then 5x would be the age of the father. In 6 years, the son would be x + 6 years old, where the father would be 3(x + 6) years old. Since the original age of the father is 5x, then in 6 years the father could also be said to be 5x + 6 years old. Setting these two expressions for the father's age as an equation, we then can solve for x, the son's age.

3(x + 6) = 5x +6

3x + 18 = 5x + 6

2x = 12

x = 6

The original age of the son is 6 and of the father (5x) is 30 years old. In 6 years, the son would be 12 and the father would be [3x + 18 or 5x + 6] 36 years old.

Q: 2 you are currently 5 times as old as your son In 6 years time you will be three times as old as he will be then What are your ages?

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Maria is 11 years old.

The sum of the ages of husband and his wife is four times the sum of the ages of their children.Four years ago,the ratio of the sum of their ages of their to the sum of the ages of their children was 18:1 two years hence the ratio will be 3:1. How many children do they have.

Suppose the cat's age is x. Then Timothy's age is 3x + 4. The sum of their ages is 44 ie x + (3x+4) = 44 or 4x + 4 = 44 or 4x = 40 so that x = 10 ie the cat is 10 years old. Then Timothy's age = 3x + 4 = 3*10 + 4 = 34.

To solve, use two statements like J=3S and J+S=36 -- to expose the ages difference and also the sum of their ages. Solving we substitute for J in the second statement and show that 3S+S=36 or S=9 -- Shanea's age. So we know that Jason is 27 -- and he had to have been 24 three years ago.

There is not enough information to find the father, nor his age.The sum of their ages, in y years' time will be 7b + 2y years.

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