2x+5=3x+1
-x=-4
x=4
2x = 3x + 1; -x = 1; x = -1.
3x+1+2x-2 = 64 3x+2x = 64-1+2 5x = 65 x = 13
Both equations are equal and so: 3x+1 = 2x+3 3x-2x = 3-1 x = 2 and by substituting y = 7
NM equals 2x + 1, as stated in the question!
(1, 1)
2x = 3x + 1; -x = 1; x = -1.
3x+1+2x-2 = 64 3x+2x = 64-1+2 5x = 65 x = 13
Both equations are equal and so: 3x+1 = 2x+3 3x-2x = 3-1 x = 2 and by substituting y = 7
3x + 5x = 2x + 28x = 2x + 26x = 2x = (2/6) = 1/3
NM equals 2x + 1, as stated in the question!
(1, 1)
3x(2x + 1)
x + 2 = 3x-1 -2x = -3x = 1,5
1
(-1, 5)
(-1, 5)
-2x + 3y = -7 3x + y = 16 simultaneous equations. Elimination a letter. Arbitrarily select 'y' Hence multiply the bottom eq'n by ' -3' Hence -2x + 3y = -7 -9x - 3y = -48 Add the eq'ns/ -11x = =55 x = -55/-11 = 5 When x = 5 , substitute into either eq'n for 'y' -2(5) + 3y = -7 -10 + 3y = -7 3y = 3 y = 1 Hence answer in ( x,y) fpr, is ( 5,1).