Solve by the substitution method the given system of the linear equations of 3 variables.
2x + 7z = 64
8y + 6z = 40
3x - 2y + 4z = 46 (add the first equation with the second equation)
2x + 8y + 13z = 104
3x - 2y + 4z = 46 (multiply the second equation by 4)
2x + 8y + 13z = 104
12x - 8y + 16z = 184 (add both equations)
14x + 29z = 288
14x + 29z = 288
2x + 7z = 64 (multiply the second equation by -7)
14x + 29z = 288
-14x - 49z = -448 (add both equations)
-20z = -160 (divide both sides by -20)
z = 8
2x + 7z = 64 (substitute 8 for z)
2x + 7(8) = 64
2x + 56 = 64 (subtract 56 to both sides)
2x = 8(divide by 2 to both sides)
x = 4
8y + 6z = 40 (substitute 8 for z)
8y + 6(8) = 40
8y + 48 = 40 (subtract 48 to both sides)
8y = -8 (divide by 8 to both sides)
y= -1
Thus, the solutions are x = 4, y = -1, and z = 8.
10 - 3x = x - 2x + 40 10 - 3x = - x + 40 10 - 40 = 3x - x -30 = 2x -15 = x
120
36 + 35 + 40 + 40 + 40 + 40 + 40 = 271 271 is the answer
25x (square) plus 40 plus 15 equals 680.
10 plus 20 plus 30plus 40 plus 50 equals 150 because 50 plus 40 equals 90 plus 30 =120+20= 140 then + 10 = 150
3x + 2x = 40 5x = 40 x = 8
Add the two equations you get 5y = 60 so y = 12 and x = 2
10 - 3x = x - 2x + 40 10 - 3x = - x + 40 10 - 40 = 3x - x -30 = 2x -15 = x
To solve for x, set up the equation: 2x +2x = 40 (then simplify) 4x = 40 (then divide both sides of the equation by 4) x = 10 (this is the answer)
y=16 x= -4
2x+9 = 49-3x 2x+3x = 49-9 5x = 40 x = 8
2x+17=6x-23 23+17=6x-2x 40=4x x=40 / 4 therefore x=10
6x-52 = 4x+40 6x-4x = 40+52 2x = 92 Answer: x = 46
7. 8x-40=2x+2 4x-20=1x+1 3x-21=0 3x=21 therefore x=7
x=20
Yes it is and well done.
x^2+2x+40 = x^2-x+190Subtract x^2 from both sides2x+40 = -x+190Add x to both sides3x + 40 = 190Subtract 40 from each side3x = 150Divide both sides by 3x = 50