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Let

f(X)=2X2+6X+3

So f(-p)=f(2q)

or 2p2-6p+3=8q2+12q+3

or p2-3p=4q2+6q

or p2-4q2=3p+6q

or (p+2q)(p-2q)=3(p+2q)

so p-2q=3

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Q: 2x to the power of 2 plus 6x plus 3 has the same remainder when divided by x plus p or by x-2q where p is unequal to -2q Find the value of p-2q?
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