Let
f(X)=2X2+6X+3
So f(-p)=f(2q)
or 2p2-6p+3=8q2+12q+3
or p2-3p=4q2+6q
or p2-4q2=3p+6q
or (p+2q)(p-2q)=3(p+2q)
so p-2q=3
226186081502
real and unequal
No. Not if there are an even number of observations and the middle two values are unequal.
7
how to find the value of 10th power of 0.4
When a number is divided by 32 what is the greatest value the remainder may have
24
The remainder is always 31 or less.
0.6667
68686868
The remainder is the number that is left over after the initial value has been divided as much as it can. If any numbers greater than 48 were present as a remainder, then these could be divided further into 48. If 48 is present as the remainder, then this can be divided by 48 to give 1, leaving no remainder. Thus, the largest possible remainder if the divisor is 48 is 47.
226186081502
The value of x must be 23 because 19*23/17 or 437/17 = 25 with a remainder of 12
273
unequal
100 divided by 25 times 64 = 256
If the remainder must be an integer value, then the largest remainder you can have from any equation when dividing by 12 is a remainder of 11. Example: (23 / 12 = 1 R11) 12 goes into 23 one time, and there's 11 left over. If there was more than 11, such as (24 / 12), then the answer would be 2 with no remainder.