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Q: What factors are multiplied to form a perfect square?

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Integral square roots are multiplied by themselves.

Pairs of numbers.

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simplest form is just the square root of 10 because there are no perfect square factors of 10

A perfect square trinomial is looking for compatible factors that would fit in the last term when multiplied and in the second term if added/subtracted (considering the signs of each polynomials).* * * * *A simpler answer is: write the trinomial in the form ax2 + bx + c. Then, if b2 = 4ac, it is a perfect square.

It is just sqrt(34) since there are no factors of 34 that are perfect squares

A trinomial is perfect square if it can be factored into the form

319 = 29 x 11. No perfect square factors, so sqrt(319).

√155 is. 155 has no factors that are perfect squares, so there's no way to simplify it.

12

Let's take a quadratic polynomial. There are three terms in a quadratic polynomial. Example: X^2 + 8X + 16 = 0 To satisfy the criteria of a perfect square polynomial, the first and last term of the polynomial must be squares. The middle term must be either plus or minus two multiplied by the square root of the first term multiplied by the square root of the last term. If these three criteria are satisifed, the polynomial is a perfect square. Let us take the above quadratic. X^2 + 8X + 16 = X^2 + 2(4X) + 4^2 = (X+4)^2 As we can see, each criteria is satified and the polynomial does indeed form a perfect square.

Write it in the form ax2 + bx + c. It is a perfect square if b2 = 4ac

Divide 2880 by 5 to give the perfect square 576 = 242. First write 2880 in its prime factorisation in power form: 2880 = 26 x 32 x 51 To be a perfect square, all the prime factors need to have an even power, so to find the smallest number by which to divide to get a perfect square only all the odd powers need to be reduced by 1; only the power of the prime factor 5 is odd and needs to be reduced by 1, so divide by 5.

perfect trinomial square?? it has the form: a2 + 2ab + b2

Yes; the factored form would be (9c+4)(9c+4) or just (9c+4)2 Since the two factors are the same, the beginning trinomial 81c2+72c+16 is a perfect square trinomial

Since 50 contains no perfect square among its factors, you can't simplify the root of 50.

âˆš65 .The factors of 65 are 13 & 5, neither of which are perfect squares.

In order to calculate this, you have to identify what you can take the square root of within 96. Two factors of 96 are 16 an 6, and 16 is a perfect square, because it is an integer that is a square of an integer, or 4 x 4. So: √ 96 = √ 16 x 6 = √ 16 √ 6 = 4 √ 6. So 4 √ 6 is the square root of 96 written in radical form.

The idea is to find a perfect square among its factors, such as two square, three square, etc. In this case, the square root of 68, root(68), equals root(4 x 17) = root(4) x root(17) = 2 root(17).

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A trinomial is perfect square if it can be factored into the form (a+b)2 So a2 +2ab+b2 would work.

First note that 84=4x21 and 4 is a perfect square. So square root of (84)=square root (4x21)=Square root (4) Square root (21)= 2 multiplied by the square root of 21. You can also write this using rational exponents, but this is not in radical form. It is an equivalent expression, however. 2 x (21)1/2

The square root of 12 is not a rational number. In fact, it is a radical number. It's simplified form would be 2 multiplied by the square root of 3.

Since 30 does not have any square factors greater than one, the expression is in its simplest form.

root 57 in radical form is √57 since 57 = 3 x 19 and there are no square factors.