Q: 3 factors of 72 that have a sum of 109?

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The first step to solving this is to break 327 up into its prime factors. The digit sum divides by 3, and so we know 3 is a prime factor. Dividing by 3 gives us 109. This is a prime number, and so the prime factors of 327 are 3 and 109. Therefore, the numbers you can divide 327 by are 1, 3, 109 and 327.

The prime factors for 72 are: 2, 3

24 and 3 24 * 3 = 72 24+3 = 27

You probably want to know "What are the 3 consecutive whole numbers whose sum is 72 ?" They are 23, 24, and 25.

If a question says solve the sum of the squares of 3 and 10, you would multiply 3 by 3 to get 9 and 10 by 10 to get 100, and add the two numbers to get 109. 32 + 102 = 9 + 100 = 109

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2 + 3 = 5

the prime factors of 72 are 2 and 3 6,12, and 1 (also factors) sum up to 19

1 + 2 + 3 + 6 + 109 + 218 + 327 + 654 = 1,320

The first step to solving this is to break 327 up into its prime factors. The digit sum divides by 3, and so we know 3 is a prime factor. Dividing by 3 gives us 109. This is a prime number, and so the prime factors of 327 are 3 and 109. Therefore, the numbers you can divide 327 by are 1, 3, 109 and 327.

The factors of 981 are: 1, 3, 9, 109, 327, and 981.The prime factors of 981 are: 3 and 109.

301.09

It is: 300+109/100 = 301.09 as a decimal

The prime factors for 72 are: 2, 3

As a product of its prime factors: 2*2*2*3*3 = 72

There are only 2 prime factors for 72. They are 2 and 3, since 72 = 2X2X2X3X3. Therefore, the 2 prime factors for 72 are 2 and 3.

The prime factors of 72 are: 2 and 3.

Factors of 327 are 1, 3, 109, and 327.