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A orthogonal polyhedron (a cube made of rectangles not squares) has 6 faces. Each opposite face will have the same area.

S.A. = 2 * (3 * 3 + 3*2 + 2*3) = 42 square feet

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I'm assuming a box. Area of smallest side is 3 x 9 ie 27 sqft.

Q: 3 feet by 3 feet by 2 feet surface area?

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72 square feet

2(lb+bh+hl)

Curved surface area = 2*pi*radius*height = 2*3.14*1*3 = 18.84 square feet Area of the 2 ends = 2*pi*radius2 = 2*3.14*12 = 6.28 square feet Total surface area = 18.84+6.28 = 25.12 square feet.

62 square feet

Entire surface area: (2*pi*32)+(6*pi*4) = 42*pi square feet or about 132 sq ft

A cylinder with a diameter of 1 foot and 3 feet high has a surface area of 11 square feet.

13.5 square feet

Surface area without the end caps = 2*pi*2*5 = 62.832 square feet rounded to 3 decimal places

2 x (11 x 3) + 2 x (11 x 3) + 2 x (3 x 3) = 150 square feet

By using the equation 2B+Ph. B=2x3=6ft P=2+2+3+3=10ft h=4ft So, 2(6)+(10)(4)=52 square feet

It is: 2(3*4)+2(3*6)+2(4*6) = 108 square feet

It is 2*(2*3 + 3*4 + 4*2) = 52 square feet.