(3c +15)/(c2 - 5) + c/(c + 5)
= (3c + 15)/(c - 5)(c + 5) + c/(c + 5)
= (3c + 15)/(c - 5)(c + 5) + [c(c - 5)/(c + 5)(c - 5)(since the common denominator is (c + 5)(c - 5)
= (3c + 15)/(c - 5)(c + 5) + (c2 - 5c)/(c + 5)(c - 5)
= (3c + 15 + c2 - 5c)/(c - 5)(c + 5)
= (c2 - 2c + 15)/(c - 5)(c + 5)
= [(c - 5)(c + 3)]/(c - 5)(c + 5) (simplify)
= (c + 3)/(c + 5)
x - 5
Without any parenthesis is: 92 - 2 * 15 + 16 - 8 = 59
15.
(x - 5)(x + 3)
x2 - 19x + 60 = x2 - 15x - 4x + 60 = x(x - 15) - 4(x - 15) = (x - 15)(x - 4)
x - 3
x - 5
It is impossible but if it were x squared plus 2x minus 15 the equation would be (x+5) (x-3) with x being equal to either -5 or 3. If the original problem was x squared minus 2x minus 15 the equation would be (x-5)(x+3) and x would be equal to either 5 or -3
(x - 5)(x - 3)
Without any parenthesis is: 92 - 2 * 15 + 16 - 8 = 59
2s2+7s-15 = (2s-3)(s+5) when factored
3x^2 -14x +15 = (3x-5)(x-3)
What about it? Factorise it?
That can be factored to -((x + 5)(x - 3))
0.0375
x = 1
15.