40 + 9 = 5y + 9
Since 9 is present on both sides of the equation,therefore we can strike it off on both sides,the remaining equation being 40 = 5y or 5y = 40
5y = 40
or y = 40/5
Therefore,y = 9 .
5y = 2y+9 5y-2y = 9 3y = 9 y = 3
(2, 1)
y=4
18y+48+5y+15 = 270 18y+5y = 270-48-15 23y = 207 y = 9
Can you help with this equation? Thanks. Solve for x and y and z for the following. x plus y plus z equals 9 x plus 2y plus 3z equals 23 x plus 5y plus -3z equals -7
Solving for y: 5y = 9 + 2y 5y - 2y = 9 3y = 9 y = 9/3 = 3
5y = 2y+9 5y-2y = 9 3y = 9 y = 3
5y + (4 - 2y) = 9 5y + 4 - 2y = 9 3y + 4 = 9 3y = 5 y = 5/3
(2, 1)
y=4
yes it is..your welcome
yes
18y+48+5y+15 = 270 18y+5y = 270-48-15 23y = 207 y = 9
Can you help with this equation? Thanks. Solve for x and y and z for the following. x plus y plus z equals 9 x plus 2y plus 3z equals 23 x plus 5y plus -3z equals -7
x = 2, y = 1
They are: x = -2 and y = -1.
7(3y-2)-(-4y+9)