The solution of the system of the two equations, 4x - y = 33 and 5y = 24 may be found by first solving the second equation for y: y = 24/5. then substituting this value into the first equation to produce 4x - (24/5) = 33, or x = [33 + (24/5)]/4 = [(189/5)/4] = (189/20).
2y + 2xy' + 4y + 4xy' = 0 6y + 6xy' = 0 y' = -y/x
It is 4xy.
4xy+1=3y-7x 4xy-3y=-7x-1 y(4x-3)=-7x-1 y=(-7x-1)/(4x-3)
4xy + x3y + yx2 + yx + 3yx = x3y + x2y + 8xy = (xy)(x2y + x + 8)
4xy - 2y(x + 4) = 4xy - 2xy - 8y = 2xy - 8y = 2y(x - 4)
2y + 2xy' + 4y + 4xy' = 0 6y + 6xy' = 0 y' = -y/x
It is 4xy.
4xy+1=3y-7x 4xy-3y=-7x-1 y(4x-3)=-7x-1 y=(-7x-1)/(4x-3)
It is 4xy.
4xy + x3y + yx2 + yx + 3yx = x3y + x2y + 8xy = (xy)(x2y + x + 8)
It is 4xy.
4xy - 2y(x + 4) = 4xy - 2xy - 8y = 2xy - 8y = 2y(x - 4)
(x + 3)(x + 4y)
the difference between 2x2 +4xy-3 and x2-2xy-4 is?
It is 4xy.
-1
3x2y - 4xy + 4x