oranges x apples y 5x+2y=72 1x+4y=48
make it so that either the x value or the y value are the same
2(5x+2y)=2(72)
1x+4y=48
here you can see how the y's are now the same
10x+4y=144
1x+4y=48
subtract the bottom equation from the top one
9x=96
divide
9x/9=96/9
x=10 2/3
substitute 10 2/3 for x in either of the original equations
1x+4y=48
1(10 2/3)+4y=48
10 2/3+4y=48
subtract
4y=48-10 2/3
4y=37 1/3
divide
4y/4=(37 1/3)/4
y=9 1/3
therefor, x is 10 2/3 y is 9 1/3
money-wise, the oranges (x) are $10.67 and the apples (y) are $9.33
Solve the problem by treating it as a simultaneous equation question which works out as: Apples: 0.20 each Oranges: 0.10 each
Oranges cost 6 cents each. Apples cost 10 cents each.
Divide the total cost of the oranges $8.05 by the number of oranges 7 to get the cost per orange 1.15 then take the cost per orange and multiply it by the 3. 8.05/7=1.15 1.15X3=3.45 3 oranges cost $3.45
4.32/36 = 0.12 per apple ( 12 cents)
It is 4 pence: an unlikely price in 2017!
An apple costs 2 cents more than an orange. 3a + 2o = 2a + 3o + 2 a = o + 2
apple = 0.45 each orange = 0.60 each
the answer is 0.47
Treat it as a simultaneous equation and it works out as: Oranges = 0.10 each Apples = 0.20 each
Solve the problem by treating it as a simultaneous equation question which works out as: Apples: 0.20 each Oranges: 0.10 each
Oranges cost 6 cents each. Apples cost 10 cents each.
one apple is for 0.45.
$0.45
Apple = $0.50 Banana = $0.35 Orange = $0.25
Divide the total cost of the oranges $8.05 by the number of oranges 7 to get the cost per orange 1.15 then take the cost per orange and multiply it by the 3. 8.05/7=1.15 1.15X3=3.45 3 oranges cost $3.45
A pair of oranges costs 90 cents and a pair of apples costs 70 cents. A pair with one of each costs 80 cents.
5 oranges cost 75p, therefore one orange costs 75/5 = 15p£2.70 = 270p.Therefore amount of oranges for 270p = 270/cost of one orange = 270/15 = 18 orange