5x3-3x plus 4 -3x3-2x2 plus 6x-1?

Answer 1

Am I right :P?

5x^(3)-3x+4-3x^(3)-2x+6x-1

Since 5x^(3) and -3x^(3) are like terms, add -3x^(3) to 5x^(3) to get 2x^(3).
(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=2x^(3)-3x+4-2x+6x-1

Since -3x and -2x are like terms, subtract 2x from -3x to get -5x.
(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=2x^(3)-5x+4+6x-1

Since -5x and 6x are like terms, subtract 6x from -5x to get x.
(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=2x^(3)+x+4-1

Subtract 1 from 4 to get 3.
(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=2x^(3)+x+3

To find the derivative of 2x^(3), multiply the base (x) by the exponent (3), then subtract 1 from the exponent.
(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=6x^(2)+(d)/(dx) x+3

To find the derivative of x, multiply the base (x) by the exponent (1), then subtract 1 from the exponent (1-1=0). Since the exponent is now 0, x is eliminated from the term.
(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=6x^(2)+1+(d)/(dx) 3

Since 3 does not contain x, the derivative of 3 is 0.
(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=6x^(2)+1+0

Add 0 to 1 to get 1.
(d)/(dx) 5x^(3)-3x+4-3x^(3)-2x+6x-1=6x^(2)+1

The derivative of 5x^(3)-3x+4-3x^(3)-2x+6x-1 is 6x^(2)+1.
6x^(2)+1