1346 gallons
1795 gallons, if you fill it to the brim.
It depends on the size of the bricks and their orientation.
598 Imperial gallons, approx.
10 ft = 3.048 metres.
This pond can hold up to 1,346,493.51 gallons of water.
A tank this size can hold a maximum of 3,590.65 US gallons of water.
The river wear is 67 miles long and 13 meters deep in the winter and 10ft at summer
Assuming that the pool has an average depth of 4' , there would be about 11,760 gal.
The diagonal is 14.142 feet.
A tank of 21 inches wide, 8 inches deep and 59 inches long will hold 36 gallons of gas. These gallons refers to US gallons.
Approximately 24.7 cubic yards or 31.7 tons of gravel.
1.5x4x6x7.48 gallons/cubic foot=269.28 us gallons
This cannot be answered as stated. There must be three dimensions given: width/depth/height. Or we must assume that the tank is "circular." More accurately, we assume the tank is a cylinder that is four feet high and 10 feet in diameter. The volume of a cylinder is given by the formula V = (Pi)r2h, where ris the radius of the base of the cylinder and h is its height. Since the radius is half the diameter, we get: V = (Pi) * (52) * 4 = 3.141 x 25 x 4 = 314.1 cubic feet of water. The question asked for the volume in gallons, however. One cubic foot of water contains about 7.48 gallons. So 314.1 x 7.48 = 2349.9 gallons.
Assuming the pipe is 15 inches = 1.25 feet in diameter, Volume = pi*D2/4*L = 12.27 cubic ft, approx. 1 cu ft = 7.4805 gallons so volume = 12.27*7.4805 = 91.800 gallons.
Approximately 8,887 gallons.
8,258.494 gallons.
1795 gallons, if you fill it to the brim.