Q: 7 P in a NT

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p + 7 = 111 subtract 7 from each side p + 7 - 7 = 111 - 7 p = 104

p + 7 = 13 p = 6

The interest is said to be compounded quarterly when compound interest is paid four times a year, and the compounding period is three months. After t years, the balance A, in an account with principal P and rate r (in decimal form) is given by the formula A = P(1 + r/n)nt In our case P = 2,800, r = 7% = 0.07, n = 4, and t = 1 year, so we have: A = P(1 + r/n)nt A = 2,800(1 + 0.07/4)(4)(1) ≈ 3,001.21 The balance after one year is 3,001.21

p + 7

probability of a machine component failing = 2/7 P(at least 4 failed) = P( 4 failed)+P(5 failed) +P(6 failed)+P(7 failed) Using binomial probability: P(4 failed ) =7C4 (2/7)^4 ((5/7)^3 = 0.084987 P(5 failed) = 7C5 (2/7)^5 (5/7)^2 = 0.020395 P(6 failed ) = 7C6 (2/7)^6 (5/7) = 0.002719 P(7 failed) = (2/7)^7 = 0.000155 Adding, P(at least 4 failures) = 0.108257

Related questions

7 players in a netball team

I'll be expecting payment!!! =] Nt really =p

As normal Windows. 2000, XP, Vista, and 7 are all technically Windows NT

it is nt a novel;it is a poem.

The last version of Windows under the "NT" brand was Windows NT 4. The latest version to be built upon Windows NT is Windows Vista (Windows 7 has not yet been releasedofficially).

it is the seventh NT that windows has put out (3.0,95,98,2000/ME,XP,Vista,Windows 7)

the answer is 7 limits

It is: p-7

p + 7 = 111 subtract 7 from each side p + 7 - 7 = 111 - 7 p = 104

C*nt. Cr*p is not really a swear word

p + 7 = 13 p = 6

The interest is said to be compounded quarterly when compound interest is paid four times a year, and the compounding period is three months. After t years, the balance A, in an account with principal P and rate r (in decimal form) is given by the formula A = P(1 + r/n)nt In our case P = 2,800, r = 7% = 0.07, n = 4, and t = 1 year, so we have: A = P(1 + r/n)nt A = 2,800(1 + 0.07/4)(4)(1) ≈ 3,001.21 The balance after one year is 3,001.21