The ordered pair is (-1, -2).
The ordered pair is (-1, -7).
If 5x plus 3y equals 13, the x equals 2 and y equals 1. This is because 5x2=10 and 3x1=3, and 10+3=13.
x = 8y = 6(5x8) + (3x6) = 58(5x8) - (3x6) = 22
2x plus 3y
The ordered pair is (6, 3).
7x+3y=-52 3(8x-y=-74) 7x+3y=-52 24x-3y=-222 7x=-52 + 24x=-222 31x=-274 x=8.8387
x = 2 and y =1 so the lines intersect at (2, 1)
1. x + y = 62. -x + 3y = -2Adding 1. to 2. gives:3. 4y = 4y = 1Substitutuing y = 1 into 1. gives:x + 1 = 6x = 5Writing our ordered pair in the form of (x,y) we have (5, 1).
These are equations of two straight lines. Provided the equations are not of the same or parallel lines, there can be only one ordered pair. So the ordered pair is - not are : (0.5, -1)
x = 3 and y = 4 so the lines intersect at (3, 4)
It works out that x = 6 and y = 3 or as (6, 3)
The coordinates of every one of the infinitely many points on the line defined by the equation is a solution.
Solve this system of equations. 5x+3y+z=-29 x-3y+2z=23 14x-2y+3z=-18 Write the solution as an ordered triple.
There are infinitely many ordered pairs. The coordinates of each of the infinite number of points on the straight line defined by 2x + 6y = 24 (or equivalently, 3y = -x + 12) is an ordered pair that satisfies the requirements.
x+y=15, or y=15-x4x+3y=38Substitute y in 2nd equation with 15-x:4x+45-3x=38x=-7y=15-(-7)=22(-7,22)
x = 12 y = 2 (12,2) satifies the equation