no its not a solution
The lines intersect at (3, 5)
-8x - 10 - 20 = -8x - 30
The simplest way is to rewrite the equation in the standard for: y = mx + c. Then the slope is m. 8x - 7y = 56 7y = 8x - 56 y = 8/7 * x - 8 So the slope is 8/7
8x - 7y + 2 = 0 The slope-intercept form is NOT the standard form. The above form is easily generalised to 3 (or more) dimensions, not so with the slope-intercept form.
8 over 7.
y=-(8/7)x+4 Therefore, the slope= -(8/7)
Y-8x plus 9y equals 10y-8x.
8x - 7y + 6
X = 1
x = 2
8x plus 4y equals 5 is 8x + 4y = 5.
11x + 8 = 8x + 20 3x + 8 = 20 3x = 12 x = 4
That's an equation where x = 5
It is: y = -8/7x+3/7 in slope intercept form
8x+4y=20 4y=-8x+20 y=-2x+5 f(x)=-2x+5
The given expressions can be simplified to: 7y-8x-14
- 8x + 8x = 0 so question is meaningless.
8x-7 plus 2x equals 6 plus 5x plus 2?
If: 21 is a plus Then : x = 20