Q: 8 minus 1 over 3x equal 16?

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I think you mean (3x ± 1)^2 = (3x+1)(3x-1)?

x = 1

X= -2 ! Since the equation must equal zero - 17+3x must equal 11. The variable 3x HAS to equal -6... therefore x is equal to minus 2.

Your question is unanswerable until you know what x & y are.

If: 15+3x = 6x-2 Then: 15+2 = 6x-3x => 17 = 3x Therefore: x = 17/3 or 5 and 2/3 as a mixed number

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2x minus 3x is equal to -x.

2x minus 3x is equal to -x.

If the question could more exactly be phrased as, "What is the value of x when 9x2 - 16 = 0", the answer is, x = 4 or -4. This answer can be found by factoring 9x2 - 16 into (3x + 4)(3x - 4) and setting each factor equal to zero.

I think you mean (3x ± 1)^2 = (3x+1)(3x-1)?

9x2 + 18x - 16 = 0 ⇒ (3x - 2)(3x + 8) = 0 ⇒ 3x - 2 = 0 → x = 2/3 or 3x + 8 = 0 → x = -22/3

x = 1

eq: 3x+5=7 =3x=7-5 =3x=2 =x=2/3

(x/4) - 4 = (3x/4) - 6 The first step to solving this equation is to multiply the entire equation by 4 to eliminate the denominators under x. Doing so yields the equation: x - 16 = 3x - 24 Simply combining like-terms will yield 2x = 8 So x is equal to 4

X= -2 ! Since the equation must equal zero - 17+3x must equal 11. The variable 3x HAS to equal -6... therefore x is equal to minus 2.

Your question is unanswerable until you know what x & y are.

3x squared minus 25x minus 28

If: 15+3x = 6x-2 Then: 15+2 = 6x-3x => 17 = 3x Therefore: x = 17/3 or 5 and 2/3 as a mixed number