If: 8-1/3x = 16
Then: x = -1/24
I think you mean (3x ± 1)^2 = (3x+1)(3x-1)?
x = 1
X= -2 ! Since the equation must equal zero - 17+3x must equal 11. The variable 3x HAS to equal -6... therefore x is equal to minus 2.
Your question is unanswerable until you know what x & y are.
-(3x-4) = -3x + 4
2x minus 3x is equal to -x.
2x minus 3x is equal to -x.
If the question could more exactly be phrased as, "What is the value of x when 9x2 - 16 = 0", the answer is, x = 4 or -4. This answer can be found by factoring 9x2 - 16 into (3x + 4)(3x - 4) and setting each factor equal to zero.
I think you mean (3x ± 1)^2 = (3x+1)(3x-1)?
9x2 + 18x - 16 = 0 ⇒ (3x - 2)(3x + 8) = 0 ⇒ 3x - 2 = 0 → x = 2/3 or 3x + 8 = 0 → x = -22/3
x = 1
eq: 3x+5=7 =3x=7-5 =3x=2 =x=2/3
(x/4) - 4 = (3x/4) - 6 The first step to solving this equation is to multiply the entire equation by 4 to eliminate the denominators under x. Doing so yields the equation: x - 16 = 3x - 24 Simply combining like-terms will yield 2x = 8 So x is equal to 4
X= -2 ! Since the equation must equal zero - 17+3x must equal 11. The variable 3x HAS to equal -6... therefore x is equal to minus 2.
Your question is unanswerable until you know what x & y are.
3x squared minus 25x minus 28
-(3x-4) = -3x + 4