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A 0.45-kg volley ball travels with a velocity of 4ms over the net. You jump up hit the ball back with a horizontal velocity of 7.0ms If contact time is 0.040 s whats the averag force on the ball?
Wiki User
∙ 15y ago
m=0.45 Kg
change in velocity= Vf - Vi =7-(-4)=11m/s.
Rate of change of velocity = (11/0.04) m/s2
Average force on ball = m x (11/0.04) = 123.75 newton Answer
Wiki User
∙ 15y ago
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