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After the nose of the train reaches the platform, it takes some number of seconds for the

nose to reach the far end. At that time, the whole train is lined up with the whole platform.

Then after that, it takes the same number of seconds again for the caboose to reach the far end,

and the train to completely clear the platform.

So the total time that there's some overlap between the train and platform is twice the time

the train takes to move the length of the platform, which is also the length of the train.

Distance = (speed) x (time)

180 meters = (speed) x (9 seconds)

speed = (180/9) = 20 meters per second

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13y ago
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Q: A 180 meter long train crosses a platform of equal length in 18 seconds what is the speed of the train?
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