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A body is falling freely how much distance it falls during an interval of time between 1st and 2nd seconds of its motion taking g 10?
Wiki User
∙ 13y ago
If G = 10, then the body's speed is 10 at the end of 1 second,
and 20 at the end of 2 seconds.
During that interval of time, its average speed is (20 + 10)/2 = 15 m/s.
The distance is (average speed) x (time) = 15 meters.
Wiki User
∙ 13y ago
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What is the distance covered by a freely falling object 5 seconds after it is dropped from rest?
0.7848 meter
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An interval is the spacing of time. For example: I ran for an interval of 10 minutes then walked for an interval of 30 minutes. Or each car has an interval of 0.5 seconds.
What is the average speed if you walk for 120 seconds at 1ms then run for 120 seconds at 6ms?
To find the average speed you must know the total distance traveled and the total elapsed. The distance traveled in each interval is simply the speed multiplied by the time (v x t). Thus, in the first interval you travel 120 x 1 = 120 meters, in the second interval 120 x 6 = 720 meters; therefore, the total distance traveled is 840 meters. The total time elapsed is 120 + 120 = 240 seconds. An average speed is simply the total distance traveled divided by the total time elapsed thus in this case it is 720 m / 240 s = 3 m/s.
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3 Seconds Two seconds
Is the recommended safe following distance in good conditions?
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To get average speed, just divide distance by time. In this case, you divide whatever distance an object moves during the 11 seconds, by the 11 seconds.
What is the distance covered by a freely falling object 5 seconds after it is dropped from rest?
0.7848 meter
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An RR interval is represented in milliseconds. Thus, to report the RR interval in seconds, simplay divide the value by 1000. e.g. RR interval of 876 divide by 1000 = 876/1000 = 0.876
