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Nickles - 10 $0.50

dimes - 20 $2.00

quarters - 40 $10.00

0.50+2.00+10.00 = $12.50 containing 40 quarters

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Here's how to solve this with Algebra :

Let N be the number of nickels, so that

2N is the number of dimes, and

2(2N) or 4N is the number of quarters.

A nickel is 5 cents, a dime is 10 cents, and a quarter is 25 cents,

and the total in the cash register is $12.50

Multiplying by their cents values, we have

5(N) plus 10(2N) plus 25 (4N) = 1250

5N + 20N + 100N = 1250

125 N = 1250

N= 10

So the number of nickels is 10, dimes 20, and quarters 40.

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โˆ™ 2010-02-09 20:37:25
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Q: A cash register contains 12.50 and there are only nickels dimes and quarters There are twice as many dimes as nickels and twice as many quarters as dimes How many quarters are in the cash register?
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