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6 litres of 50% + 4 litres of 25%

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Q: A chemist has one solution which is 50 percent acid and a second solution which is 25 percent acid how much of each should be mixed to make a 10 liters of a 40 percent acid solution?
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A chemist has one solution that is 80 percent acid and another solution that is 30 percent acid How much of the second 30 percent solution is needed to make a 400 L solution that is 62 percent acid?

144liters


A chemist has one solution that is 80 percent acid and another solution that is 30 percent acid how much of the second 30 percent solution is needed to make a 400L that is 62 percent acid?

.80x+.30y=400*.62 .80x+.30y=248 This is equation one. x+y=400 x=400-y This is the second equation. .80(400-y)+.30y=248 320-.80y+.30y=248 -.50y=-72 Y=144 X=256 CHECK .80(256)+.30(144)=400(.62) 204.8+43.2=248 248=248


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