It will have 7 sides
If a polygon had 166 sides it would have 83 diagonals as each diagonal must join two vertices.
The formula is: 0.5*(n2-3n) where n is the number of sides of the polygon. So: 0.5*(81-27) = 27 diagonals
The formula is: 0.5*(n2-3n) whereas n is the number of sides So: 0.5*(352-105) = 560 diagonals
It is an octagon with 8 sides. Let n be the number of sides = number of vertices. Then each vertex can be connected to n-3 other vertices, giving n(n -3) connections. However, this counts each vertex pair connection twice, so there are: n(n - 3) / 2 diagonals. Thus if there are 20 diagonals: n(n - 3) / 2 = 20 n2 - 3n = 40 n2 - 3n - 40 = 0 (n + 5)(n - 8) = 0 so n = -5 or 8. As a polygon cannot have a negative number of sides, n = 8.
5(5-3)/2. That it is the formula so that shape would have 5 diagonals. n(n-3)/2 where n is the number of sides
A polygon with 14 diagonals will have 7 sides
how many diagonals are there iin a polygon of 11 sides
A polygon that has 104 diagonals will have 16 sides
That polygon is called a "triangle". It has no diagonals.
A 7 sided polygon has 14 diagonals
38 diagonals
There are 77 diagonals
The five sided Polygon has 5 diagonals
An heptagon has 7 sides and 14 diagonals
It has 20 diagonals
It will have ten sides
Number of diagonals = 1/2*(n2-3n) where n = the number of sides of the polygon.