A random sample of size 36 is taken from a normal population with a known variance If the mean of the sample is 42.6. Find the left confidence limit for the population mean.
Since each event is independent, the probability remains at 0.5.
It is 60/100 = 0.6
ye
It is 1/2.
The probability is 1/4
Since the probability of getting tails is 50% or 0.5, the probability of three tails would be 0.5*0.5*0.5=0.125 or 12.5 %
The probability of a flipped coin landing heads or tails will always be 50% either way, no matter how many times you flip it.
Since each event is independent, the probability remains at 0.5.
you are looking for the probability of getting one tail, two,......., and six this equivalent to saying 1 - the probability of not getting any tails (or getting 6 heads = (1/2)^6). P(X>=1) = 1 - (1/2)^6=
It is 60/100 = 0.6
The probability of tossing a coin twice and getting tails both times is 1 in 4, or 25%. If you have already tossed a coin and had it land on tails, the probability that it will land on tails again the next time you toss it is 50%.
The probability is 0.5The probability is 0.5The probability is 0.5The probability is 0.5
The probability of getting zero tails is 1/2. The probability of getting zero tails twice in a row is 1/2 x 1/2 = 1/4. The probability of getting zero tails three times in a row is 1/2 x 1/2 x 1/2 = 1/8, etc... .
ye
2 to 1
It is 0.2503, approx.
The probability of obtaining 4 tails when a coin is flipped 4 times is: P(4T) = (1/2)4 = 1/16 = 0.0625 Then, the probability of obtaining at least 1 head when a coin is flipped 4 times is: P(at least 1 head) = 1 - 1/16 = 15/16 = 0.9375