If it is a fair die that is rolled once, then the probability is 2/3.
5/6 = 83.3%
It is 1/2 if it is a fair number cube which is rolled once.
it depends on how many numbers are on the number cube. if it only goes to 6, then the probability is 1/6. if it goes to 8 then the probability is 2/8. and so on and so on...
1 out of 2
The probability is 1, if the dice are rolled often enough.
There is a 1 in 2 chance, so 1/2.
The probability is 1. It is a certainty that you will roll a number between and including one and six. The probability of rolling each individual number is 1/6.
P(1 or 6)
the probability is 2/6
When a number cube is rolled twice, there are 36 possible outcomes. (1,1),(1,2),....(6,6). (3,3) occurs only once. Therefore, the probability of rolling a 3 both times is 1/36.
The probability that 14 is rolled at least once is 1 - 5.5*10-32 which, for all intents and purposes, can be treated as 1.
The probability of a one being rolled in a fair die is 1 in 6, or 0.1666... . The probability of a one not being rolled is 5 in 6, or 0.8333... . The probability, then, of exactly one one being rolled in nine rolls is 1 in 6 times 5 in 6 to the 8th power, or about 0.0388.
If two dice are rolled once, the probability is 30/36 = 5/6
The answer depends on how many rolls. If there were n rolls, then the probability is n*(1/6)*(5/6)n-1/[1 - (5/6)n]
50% A 6-sided die has 6 possible numbers that you can roll. 3 of those are even (2,4,6) That means three of the six possible outcomes will be positive. 3 divided by six is 50%
The favourable outcomes are 1, 3, 5 or 6 so the probability is 4/6 = 2/3
Prob = 4/36 = 1/9
When a die is rolled once, the probability of 1 showing up is 1/6 . When a die is rolled 14 times, the probability of 1 showing up 6 times is a binomial probability. Let x = number of times 1 shows up P(x=6) = 14C6 (1/6)^6 (5/6)^(14-6) = 14C6 (1/6)^6 (5/6)^8 = 0.014982
obviously it is a 50-50 chance
There are two possibilities for rolling three once, so the probability of this even is 2/36 or 1/18. Since each roll is an independent event, the total probability is: P(rolling three three times) = (1/18)3 = 1/5832
The probability of getting a sum of 2 at least once is 0.8155
There are 6 sides on a die, so the denominator should be 6. The number 3 appears on the dice once, so the fraction probability should be 1/6.