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A dinner plate has an 11 inch diameter and a salad plate has an 8 inch diameter how many more square inches does the dinner plate cover than the salad plate?
Wiki User
∙ 14y ago
The area of a plate (which we are assuming is in the shape of a circle) is
A=(pi)(radius)^2
A diameter is (2) times the (radius). The area of the dinner plate is (3.14)(5.5)^2 = 94.99
The area of the salad plate is (3.14)(4)^2 = 50.24
Now, subtract the area of the smaller plate from the larger plate. Therefore, 94.99 - 50.24 = 44.75.
Therefore, the dinner plate is approximately 44.74 in^2 more than the salad plate.
Wiki User
∙ 14y ago
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