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Q: A fair nickel and a fair dice are tossed once outcomes match when both coins land on heads or both coins land on tails What is the theoretical probability of a match?

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Since there are 6 possible outcomes, and you want the probability of obtaining one of the outcomes (in your case 6), the probability of it landing on a 6 is 1/6.

The probability is 3/4.

Assuming that it is a fair coin, the probability is 0.9990

The probability of the coin coming up heads each time is 1/8; likewise for 3 tails. The probability of getting 2 heads and 1 tail (in any order) or 2 tails and 1 head, is 3/8. There are lots of other events whose probability can be calculated when a coin is tossed 3 times, but the question doesn't specify what event is to have its probability calculated.

The answer depends on the experiment: how many coins are tossed, how often, how many dice are rolled, how often.

Related questions

The probability is 0.5

Since there are 6 possible outcomes, and you want the probability of obtaining one of the outcomes (in your case 6), the probability of it landing on a 6 is 1/6.

There are 6 outcomes, a 2 is one of them so the probability is 1/6.

1/2 (equal to 0.5, or 50%).

HHHH, HHHT, HHTT, HTTT, TTTT. Pr(HHTT) = 6/16 = 0.375

This question can be rather easily answered, as soon as outcomes 'a' and 'b' are defined.

The favourable outcomes are 1, 3, 5 or 6 so the probability is 4/6 = 2/3

If a coin is tossed 15 times there are 215 or 32768 possible outcomes.

There are 25 = 32 possible outcomes.

Two

Each coin has two possible outcomes, either Heads or Tails. Then the number of outcomes when all 4 coins are tossed is, 2 x 2 x 2 x 2 = 16.

When two fair coins are tossed, you have the following possible outcomes: HH, HT, TH, TT. So, at most implies that you get either i) zero heads or ii) one head. From the possible outcomes we see that 3 times we satisify the outcome. Thus, probability of at most one head is 3/4.

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