2
-1, 3
It is (-1, 3).
We will be able to identify the answer if we have the equation. We can only check on the coordinates from the given vertex.
In the form y = ax² + bx + c the axis of symmetry is given by the line x = -b/2a The axis of symmetry runs through the vertex, and the vertex is given by (-b/2a, -b²/4a + c). For y = 2x² + 4x - 10: → axis of symmetry is x = -4/(2×2) = -4/4 = -1 → vertex = (-1, -4²/(4×2) - 10) = (-1, -16/8 - 10) = (-1, -12)
Because the base of a cone is round, it is the only three dimensional figure with only one vertex.
It is a turning point. It lies on the axis of symmetry.
It is (-1, 3).
true
Because they represent a pair of coordinates
i think that the range and the domain of a parabola is the coordinates of the vertex
Only equilateral triangles and some irregular polygons of (3n) sides have 3 lines of symmetry. A regular polygon with n sides (or vertices) has n lines of symmetry. If n is even, there are n/2 lines of symmetry from vertex to opposite vertex and another n/2 from the middle of a side to the middle of the opposite side. If n is odd, there are n lines of symmetry from vertex to the midpoint of the opposite side.
False
y = 2x2 + 3x + 6 Since a > 0 (a = 2, b = 3, c = 6) the graph opens upward. The coordinates of the vertex are (-b/2a, f(-b/2a)) = (- 0.75, 4.875). The equation of the axis of symmetry is x = -0.75.
It depends on what the coordinates of the first three vertices are!
The vertex is at the origin of coordinates ... the point (0, 0).
axis of symmetry is x=0 Vertex is (0,0) So the answer is : YES
In a regular pentagon, the lines of symmetry are drawn from each vertex to the midpoint of the edge directly opposite the vertex, so there are five in all.
Vertex = (0,0) Line of symmetry = y axis You should of known that as this function is only X^2