21 ft how is the equation to give you this result
The statue is 6/2 = 3 times the length of its shadow. The flagpole is 3 times its shadow ie the flagpole is 3*10 = 30 metres.
The flagpole is 26 feet, 3 inches tall. (210/8 feet = 26.25 feet)Since the ratio of height to shadow is 6/8, the flagpole is also 3/4 as tall as its shadow.6/8 (man) = x/35 (pole)6/8 (35) = x210/8 = xx = 26.25 feet
28 feet
It is nearly 40 feet
The flagpole is 14 feet tall - all of the shadows (at that particular time of day) are twice the length of the object. You can compare any values at that time, and the ratios are the same: x/ 28 = 4/8 (= 1/2) x = 14
Ten is to two as 40 is to x, yielding: 200ft.
5
The statue is 6/2 = 3 times the length of its shadow. The flagpole is 3 times its shadow ie the flagpole is 3*10 = 30 metres.
1.8 meters. The ratio of object to shadow is 10:6. Therefore if the object is 3, the shadow is 1.8 ( 6/10x3).
pyramid
The flagpole is 15.92 metres, approx.
84 feet tall
It works out as: 42.353 feet tall rounded to 3 decimal places
First, find the ratio of fencepost-height : shadow which is 1.6 : 2.6 . This can also be written as a fraction, 1.6/2.6 . Then, multiply the flagpole's shadow by this ratio: 31.2 x 1.6/2.6 = 19.2 The flagpole is 19.2m high. The trigonometry way: On the imaginary right angled triangle formed by the fencepost and its shadow, let the angle at which the hypotenuse meets the ground = θ sinθ = 1.6/2.6 sinθ = /31.2 x/31.2 = 1.6/2.6 2.6x = 31.2 * 1.6 = 49.92 x = 19.2 The flagpole is 19.2m high.
The positioning of the sun throughout the day.
When the light source is directly over it or at night.
Just over 228 feet.