Accept 3 natural numbers and check whether it firms pythagorean triplet
Algorithm Step1: Read A, B, C Step2: If A > B is True, then check whether A > C, if yes then A is greatest otherwise C is greatest Step3: If A > B is False, then check whether B > C, if yes then B is greatest otherwise C is greatest Give the Flowchart Answer
first we write start and then read number and after that check the number is totaly divide by 2 or not if number is totally divide by 2 then number is even else number is odd.
Perhaps you mean an automorphic number? Loop through a series of numbers - for example, all numbers from 1 to 10,000 - and check each of the numbers, whether the condition applies. The condition in this case is that if you square the number, the last digits represent the original number.
Loop through some numbers - for example, 2 through 100 - and check each one whether it is a prime number (write a second loop to test whether it is divisible by any number between 2 and the number minus 1). If, in this second loop, you find a factor that is greater than 1 and less than the number, it is not a prime, and you can print it out.
class Twin_Prime { void Prime(int n,int m) { int a=0; int b=0; for(int i=1;i<=m+n;i++) { if(m%i==0) { a=a+1; } if(n%i==0) { b=b+1; } } if(a==2) if(b==2) { if(m-n==2) { System.out.print("The numbers "+m+" and "+n+" are Twin Prime"); } else if(n-m==2) { System.out.print("The numbers "+m+" and "+n+" are Twin Prime"); } } else { System.out.print("They are not Twin Primes"); } } }
If you mean the three numbers, 12, 16, and 18 - try it out! Use a calculator to check whether 122 + 162 = 182 or not.
Algorithm Step1: Read A, B, C Step2: If A > B is True, then check whether A > C, if yes then A is greatest otherwise C is greatest Step3: If A > B is False, then check whether B > C, if yes then B is greatest otherwise C is greatest Give the Flowchart Answer
It is a table, or a series of tables, depending on whether it is the year as a whole or month by month.
The flowchart above starts with the number 2 and checks each number 3, 4, 5, and so forth. Each time it finds a prime it prints the number and increments a counter. When the counter hits 100, it stops the process. To determine whether a number is prime, it calls the function "IsThisNumberPrime" which is shown at the top of this page.
Absolutely! That is like asking whether the Pythagorean Theorem has to do with right triangles!
I'll write it as pseudocode; you can easily convert it to a flowchart. If your number is more than 0 (Your number is positive) else if your number is less than 0 (your number is negative) else (your number is equal to zero)
If two sides of a triangle with a right angle are known, the Pythagorean Theorem can help you find the third one. It can also be used to verify whether a certain triangle is, indeed, a right triangle (if the three sides are known).
If you know two sides of a right triangle, the Pythagorean Formula lets you find the third side. Also, if you know all three sides of a triangle, you can confirm whether it is, or isn't, a right triangle.
If the lengths of the sides of the triangle can be substituted for 'a', 'b', and 'c'in the equationa2 + b2 = c2and maintain the equality, then the lengths of the sides are a Pythagorean triple, and the triangle is a right one.
That depends what you mean with "and": whether you want to add the numbers, multiply them, etc.That depends what you mean with "and": whether you want to add the numbers, multiply them, etc.That depends what you mean with "and": whether you want to add the numbers, multiply them, etc.That depends what you mean with "and": whether you want to add the numbers, multiply them, etc.
For the 6:8:10 triangle, area = perimeter = 24. Also, for the 5:12:13 triangle, area = perimeter = 30. Whether these are indeed the only examples I am not sure. That would take some proving.
For the 6:8:10 triangle, area = perimeter = 24. Also, for the 5:12:13 triangle, area = perimeter = 30. Whether these are indeed the only examples I am not sure. That would take some proving.