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The man has 13 dimes and 7 quarters, which equate to $3.05

$1.30 + $1.75

If he had 13 quarters and 7 dimes he would have $3.95

$3.25 + 70c

The method used to work this out was dividing 90c by the difference between the value of a dime and a quarter- i.e. 15c . 90 / 15 = 6, so of 20 coins, 6 more were dimes than quarters. Subtract 6 from 20, then halve the result = 7 the lower number is 7, the higher number is 7+6, = 13.

Please also note that 'Quarters' is spelled with 2 'r's

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Q: A man has twenty coins consisting of dimes and quarters if the dimes were quarters and quarters were dimes hw would have ninety cents more then he has now how many dimes and quarters does he have?
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