Top Answer

A number is divisible by 4 if the last two digits are divisible by 4.

A number is divisible by 4 if the last two digits are divisible by 4.

A number is divisible by 4 if the last two digits are divisible by 4.

A number is divisible by 4 if the last two digits are divisible by 4.

🙏

4🤨

0😮

0😂

0A number is divisible by 4 if the last two digits are divisible by 4.

🙏

0🤨

0😮

0😂

0Loading...

A number divisible by 123456789 must be 0 or bigger than 123456789. It must, therefore have 1 digit or 9 digits (or more). A remainder of 1 makes no difference to the number of digits. In any case, there can be no number of 4 digits that is divisible by 123456789.

There is no easy test for divisibility by 7, it is often just as quick, if not quicker, to do the division than any devised test. One test I can suggest: 1) split the number into blocks of 3 digits starting from the right hand end (just like when inserting commas to make a number easier to read); 2) Separately sum the units digits, tens digits and hundreds digits of each block by alternately subtracting and adding starting from the right hand end; 3) Add the sum of the units digits to 3 times the sum of the tens digits to twice the sum of the hundreds digits; 4) if the sum in step 4 is divisible by 7, then so is the original number. got 473: 3 +3×7 + 2×4 = 32 which is not divisible by 7, so 473 is not divisible by 7.

No, this number is divisible by 3 and hence is not a prime number. You can tell that fast by adding the individual digits. If that sum is itself divisible by 3, as this one is, then the number itself is divisible by 3.

Just think of one. All numbers are divisible. But that's probably not what you wanted to know. It's more likely you want to know how to find what a number is divisible by. For that, it is necessary to familiarize yourself with the rules of divisibility. If the number is even, it's divisible by 2. If the sum of the digits is a multiple of 3, the whole number is divisible by 3. If the last two digits are a multiple of 4, the whole number is divisible by 4. If the last digit is a 0 or a 5, the whole number is divisible by 5. If the number is even and divisible by 3, it's divisible by 6. If the last digit doubled subtracted from the rest is a multiple of 7, the whole number is divisible by 7. If the last three digits are a multiple of 8, the whole number is divisible by 8. If the sum of the digits is a multiple of 9, the whole number is divisible by 9. If the number ends in 0, it's divisible by 10.

A delectable number has nine digits, using the numbers 1-9 once in each digit. The first digit of a delectable number must be divisible by one. The first and second digits must be divisible by two, the first through third must be divisible by three, etc. There has only been one delectable number discovered: 381654729.

6 is the first number that's divisible by any one of those digits, or all three.

65

261, 264, or 267

97 is one example.

A prime number is one that has only two factors: one and itself.You can tell if a number is prime quickly by using the Laws of Divisibility:Numbers that end in 0, 2, 4, 6, and 8 are divisible by 2.If the sum of a number's digit is divisible by 3, the number itself is divisible by 3.If the last two digits of a number are divisible by 4, the number itself is divisible by 4.If a number ends in 0 or 5, it is divisible by 5.If a number is divisible by both 2 and 3, it is divisible by 6.If you double the last digit and subtract it from the rest of the number and the answer is 0 or divisible by 7, it is divisible by 7. For example, 4364: 4 doubled is 8. 436 - 8 = 424. You still cannot readily tell if the number is divisible by 7, so you can do it again: 4 doubled is 8. 42 - 8 = 34. 34 is not divisible by 7 so 436 is not divisible by 7If the last three digits of a number are divisible by 8, the number itself is divisible by 8.If the sum of the digits of a number is divisible by 9, the number itself is divisible by 9.If a number ends with 0, it is divisible by 10.If you add every other digit and then subtract the rest of the digits and the answer is 0 or is divisible by 11, the number itself is divisible by 11. For example: 1364: 1+ 6 = 7 and 7 - 3 - 4 = 0. The number is divisible by 11.If the number is divisible by 3 and 4, it is divisible by 12.There are more divisibility rules that can be used for large numbers.

if one of its factors are a 3 or after dividing a number by 3, their are no remainders There is also another trick: add all of the digits of the number together. The original number is divisible by 3 if and only if the sum of the digits is divisible by 3. For example: 321 is divisible by 3 because 3+2+1=6 and 6 is divisible by 3. 322 is not divisible by 3 because 3+2+2=7 and 7 is not divisible by 3.

Consecutive identical digits could be digits that are the same and appear next to one another in a number. For example, the hundreds and tens digits in 1442 could be considered consecutive identical.

1

Here's one way to find a number that is divisible by 3: If the digits of the number add up to 3, 6, or 9, then it is divisible by 3. For example, 321 is divisible by 3 because 3+2+1=6. (If the sum of the digits isn't one digit, just add those digits as well until you get to one digit (for example, 999--> 9+9+9=27, 2+7=9))

51, 52, 53, 56, 57, 58, 59

If the number is even, it is a multiple of 2 If the sum of the digits make a number divisible by 3, the number is a multiple of 3 If the number ends in 5 or 0, the number is a multiple of 5 If the number is divisible by 2 and 3, the number is a multiple of 6 If the sum of the digits make a number divisible by 9, the number is a multiple of 9

There are many possible solutions. One such is 132486970

You are 45. Remember, if a number is divisible by 5, then it must either end in 0 or 5. Therefore, since your digits are one apart, your only possibilities are 10, 45, and 65. Now, if a number is divisible by 3, the digits of that number add up to a number that is divisible by three. Of your three possibilities, this only works with 45 since 4 + 5 = 9 and 9 is divisible by 3. Hence, you are 45.

To find out if 1859 is a prime number, use the rules of division:1859 is not an even number, so it is not divisible by 2.The digits of 1859 add up to a number that is divisible by 3, so it is not divisible by 3.The last two digits (59) is not divisible by 4, so neither is 1859.The last digit is not 5, so it is not divisible by 5.1859 is not divisible by 2 and it is not divisible by 3, so it is not divisible by 6.When you double the last digit (9 doubled is 18), and subtract that number from the rest of the number (859 - 18 = 841), if the answer is 0 or divisible by 7, the number itself is divisible by 7. If you can't readily tell if the number is divisible by 7, you can do the steps again. Starting with 841, doubling the 1 is still 1, so take 1 away from 84 to get 83. 83 is not divisible by 7, so neither is 1859.The last three digits (859) are not divisible by 8, so 1859 is not divisible by 8.If the sum of the digits is divisible by 9, the number is divisible by 9. The sum of the digits is 23, which is not divisible by 9.1859 does not end with a 0, so it is not divisible by 10.If the sum of every second digit (8 + 9) minus the sum of the other digits (1 + 5) equals 0 or is divisible by 11, the number itself is divisible by 11. 17 - 6 = 11, so 1859 is divisible by 11.Since 1859 is divisible by 11, it is a composite number (a number that has at least three factors: 1, the number itself, and at least one oher factor).

No. The number 74 is not divisible by 4. One trick is to add the digits of the number and see if it is divisible by four. this trick applies only to the number 4 7+4= 11 11 is not divisible by 4.

14

10,080 is one such number.

one hundred and thirty three

No, not necessarily. 121 is a palindrome number with 3 digits (odd) and is divisible by 11. So this satisfies the premise, but 101, 111, 131, etc are not divisible by 11.An example which satisfies the premise does not prove it true, but one which contradicts the premise is enough to prove it false.

Look at the last digit (the ones, or units, digit) of the number: * if it is even, ie one of the digits {0, 2, 4, 6, 8}, then the number is divisible by 2; otherwise * it is an odd number, ie one of {1, 3, 5, 7, 9}, and the number is not divisible by 2.