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A pool can be filled by one pipe in 7 hours and by a second pipe in 2 hours How long will it take using both pipes to fill the pool?
Wiki User
∙ 14y ago
In one hour first pipe fills 1/7th of pool, other pipe fills one-half,
so together in one hour they fill 1/7 + 1/2 ie 9/14 so would take 14/9 hours (93 and a third minutes) to fill the pool. ie 1 hr 33 min 20 sec
Wiki User
∙ 14y ago
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What is 270 minutes in hours using decimals?
There are: 270/60 = 4.5 hours
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0.16 hundred hours, using the 24 hours system. 12.16 am, using the 12 hour system (am, pm).
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11,395.8 hours using 365.25 days to account for if the year is a leap year, 11,388 hours if the year is a normal year, and 11,419.2 hours if the year is a leap year. The most likely answer would be the one using 365 days, so 11,388 hours.
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+ when scientists are using 4098 hours for observing, and another 2135 hours for writing
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A swimming pool can be filled using pipes Using pipe alone it takes 12 hours using both it takes 8 47 hours. How long does it takes using the hose alone?
If you want us to solve your homework, at least copy them here correctly. The question probably starts something like "A swimming pool can be filled using a pipe and a hose"...
What are the advantages of using larger pipes?
Larger pipes may be needed to ensure sufficient water pressure. For example, a larger pipe may be needed for sufficient water pressure from the first floor to the second floor of a house.
When should you use joint compound on copper pipes?
=== === By the way I doubt very seriously your using copper pipes your using copper TUBING
9 large pipes drains a pond in 8 hours and 6 small pipes drains a pond in 16 hours How long will 3 large pipes and 5 small pipes take to drain a pond?
If 9 large pipes take 8 hours to drain the pond, then 1 large pipe would take 8*9=72 hours. large_pipe_rate = (1/72) pond/hour Since 6 small pipe drain the pond in 16 hours, then 1 small pipe would take 6*16 = 96 hours. small_pipe_rate = (1/96) pond/hour Now we can calculate using: rate * time = work done In this case, we have two rates, but a common time, so we will have: (3*large_pipe_rate)*time + (5*small_pipe_rate)*time = 1 Plug in the values we know and solve for "time": (3*large_pipe_rate)*time + (5*small_pipe_rate)*time = 1 (3 * (1/72))*time + (5 * (1/96))*time = 1 (3/72)*time + (5/96)*time = 1 (3/72 + 5/96)*time = 1 time = 1/(3/72 + 5/96) time = 1/.09375000 time = 10.66666667 Answer: 3 large pipes and 5 small pipes could drain the pond in 10 and 2/3 hours (which is 10 hours and 40 minutes). ----------------------- The other answers disagree with me. I would like you to get this problem correct, and to be honest, I'd like the points for showing the correct way to do it. So, I'll take a moment to show you why the other answers don't even make sense. Consider if all 8 pipes were large. We know that *9* large pipes could drain the pond in 8 hours. With a little calculation, we can see that 8 large pipes could drain it in 9 hours: 8 * (1/72) * time = 1 (1/9) * time = 1 time = 9 hours If all 8 pipes were small, then it would take: 8 * (1/96) * time = 1 (1/12)* time = 1 time = 12 hours So we **know** it will be somewhere between 9 and 12 hours. Certainly NOT 16 hours. Go back to the problem statement and notice that 6 small pipes can drain the pond in 16 hours. The other answers claim that 5 small pipes + 3 large pipes also take 16 hours. Therefore, their claim is that: 6 small pipes = 5 small pipes + 3 large pipes In other words, by removing 1 of the 6 small pipes and adding 3 large ones, the drain time remains at 16 hours: 1 small pipe = 3 large pipes Nonsense. Bottom line: 3 large + 5 small will take 10 hours and 40 minutes.
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