Using Pythagoras' theorem its width is 6 units in length.
Diagonal = 18.867 feet.
18.9 feet
A = 48 units2
The best way to do this would be to use the Pythagorean Theorem, but in reverse. So let's say the diagonal is 10, and the width is 8. You would do (10^2) / (8^2). This equals 36. The square root of 36 is 6. So your answer would be 6 for the length. Hope this answer helps!
The perimeter of a rectangle with length of 10 miles and width of 5 miles is 30 miles.
Diagonal = 10 meters.
Diagonal = 18.867 feet.
The diagonal is 15.620 meters.
18.9 feet
18.9 feet
Use Pythagoras: diagonal² = length² + width² → diagonal² = (10 cm)² + (15 cm)² → diagonal = √(10² + 15²) cm = √325 cm = 5 √13 cm ≈ 18 cm
A = 48 units2
The simplest Pythagorean triangle is 3, 4 and 5. Double this gives 6, 8 and 10 so the sides of your rectangle are 6 cm & 8 cm.
The best way to do this would be to use the Pythagorean Theorem, but in reverse. So let's say the diagonal is 10, and the width is 8. You would do (10^2) / (8^2). This equals 36. The square root of 36 is 6. So your answer would be 6 for the length. Hope this answer helps!
Width of rectangle: 50/10 = 5 cm
The perimeter of a rectangle with length of 10 miles and width of 5 miles is 30 miles.
length is 30 width is 10