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Q: A rectangle has a length that is twice as long as its width and a perimeter of 36 What is its area?

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If the length of a rectangle is twice its width and it has a perimeter of 48, then the rectangle is 16 in length and 8 in width.

The length of a rectangle is twice its width. If the perimeter of the rectangle is , find its area.

The perimeter of a rectangle is twice the sum of the width and length: perimeter = 2 x (4.6in + 12.1 in) = 33.4 in

Length = (Perimeter - twice width) / 2

If the width is 9' and the length is twice that, the length is 18'; the perimeter is twice the length plus twice the width, which is 36' + 18' = 54 feet.

A rectangle has two dimensions, length and width. You haven't said what the width is. The perimeter is the distance around the rectangle. Imagine going round it. You would go 42 inches, then a width, then another 42 inches, then another width. In general, the perimeter of a rectangle is twice its length plus twice its width.

Area is length times width, perimeter is twice the sum of length and breadth.

The perimeter of any rectangle is twice the sum of the length and the width of the rectangle; in the present instance, 2(n + 2n) = 6n.

156 It is impossible to calculate the area of a rectangle from its perimeter if no other dimension is known. The area of a rectangle is the product of its length and width, and the perimeter is twice the sum of its length and width.

The length is 20 units and the width is 10 units

12 meters

20 cm

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