-- a car on cruise control rolling along at a constant speed on a straight section of highway -- a golf ball or squash ball rolling across the gym floor at a constant speed
The net force will be zero only if the velocity is constant, which means acceleration is zero.
Consider a ball rolling on ice. After I toss the ball onto the ice, there will be no forces acting on the ball, other than gravity and the normal force from the ice. Thus, the net force will be zero. Due to Newton's second law, force = mass*acceleration, the acceleration must be zero. Note that this only applies to the center of mass. If you are worried about the angular acceleration of the object, you still don't have reason to be worried. The speed at which the ball is rolling does not change on frictionless ice. Thus, the angular velocity is constant. Angular acceleration must then be zero. (Otherwise the angular velocity would change.)
The acceleration of the ball can be easily found using the kinematic equation if = vi + at. Where vi = initial velocity, if = final velocity, a = acceleration, and t = seconds. The acceleration is -0.1 m/s^2.
It just does, in the absence of other forces ( ie air and rolling resistance ), that is to say under ideal conditions, a constant force on a fixed mass will produce uniform acceleration (velocity change) acceleration ( (m/s)/s ) = force (newtons) / mass (kg)
A bowling ball rolling straight down the alley. The best example of velocity without acceleration would be a spaceship that is drifting in free space with no huge gravitating bodies[planets or stars nearby]. On earth or even on a very smooth bowling alley table there is always some frictional force that is contributing a corresponding deceleration however small. A bowling ball set in motion has acceleration during the initial push to get it moving. A skydiver who has opened his parachute, reached terminal velocity, and is now drifting down at constant speed, has velocity and no acceleration.
Momentum is the product of mass and velocity. When an object slows down, the object reduces in velocity. Since Mass is constant, when velocity reduces momentum reduces. thus momentum can be what stops a rolling object. However, a resistive force the reason for the reduction of velocity and subsequently halting.
The cart will move at a constant velocity.
Magnitude of acceleration = (change in speed)/(time for the change) = (-3)/(30) = -0.1m/s2 .We can't say anything about the direction of acceleration, because there's noinformation about the direction of the ball at any time during the observation.To be honest about it, the question says "velocity" twice, but it only tells usspeed, not velocity.
If a ball is rolling in a straight line and you push it to the right velocity will accelerate.
Consider the gravitational pull of the earth and acceleration due to gravity. When you throw a ball in the air, at the highest point, it is stopped and has a velocity of 0. However, if the acceleration of the ball was also 0, then the ball would not be able to come back down to the earth. In order for the ball to come back down, there must be an acceleration. This acceleration is the acceleration due to gravity which is constant at the surface of the earth at 9.8 m/s^2. Another example: Say a car is rolling down a hill backwards. In order to stop the car from rolling more, the driver accelerates. After a certain amount of time, the car will stop (with velocity of 0) and then it will start moving up the hill again. When it is stopped, the car is still accelerating in order to overcome the force of gravity pulling the car down the hill.Technically, an object is accelerating if it's changing it's velocity. This includes speeding up, slowing down, and turning. So, yeah, if an object isn't moving at all, but is turning, it's still accelerrating.
if you increase the force , the mass remaining constant, a new rate of acceleration applies in the order a = f/m from that point (second law)
Motion with constant velocity is motion without acceleration. That is, there is no force being applied to the object in motion. One could argue that the acceleration is constant in that case, but the constant value is zero. Now, general relativity tells us that gravity and acceleration are indistinguishable from each other for a point mass being affected by either (meaning that if you're accelerating, you cannot tell just by the effect of the force whether it's due to an actual force, F=ma, or another massive object causing gravitational attraction). So in some ways, one could argue that the force of gravity is identical to constant acceleration. The difference is that gravity is caused by the presence of mass which "warps" space-time, so the acceleration felt is actually caused not by a force acting directly on the object, but the object is moving at a "constant velocity" in the equivalent flat (non-warped) space-time, and due to the presence of another mass causing a gravitational attraction, acceleration is felt. Think of it as standing on the center of a mattress. Your weight causes the middle of the mattress to push down, and if you had something like a basketball sitting in the corner of the mattress, it would begin rolling toward you. In that example, the mattress is space-time, the basketball the body in motion, and you the mass causing gravitational attraction. In that sense, since the object would be moving at a constant velocity in a flat space-time (like the ball sitting still on the mattress), warping space-time does not apply a true force to the ball, the causes it to appear to accelerate nonetheless. This appearance is due not to a force acting directly on the ball, but acting on the space-time in which it inhabits.
The acceleration of a tennis ball rolling down an incline depends with two factors. The force that is applied to the tennis ball and the mass of the tennis ball will determine its acceleration.
If a ball is rolling in a straight line and one pushes it to the right, it's velocity reduce.
Not necessarily. If it's rolling in a straight line on a smooth and level floor, then the acceleration is as good as zero. But if the ball is rolling up a hill, or down a hill, or around the groove in a roulette wheel, or through grass and slowing down, then there's substantial acceleration.
Depends on the slope.
It is an example of inertia.
Acceleration:If the ball is rolling down a uniform plane, the acceleration remains constant.Assuming the plane to be frictionless the value of acceleration will be equal to g times sin(Θ). (That is a = g x sin(Θ) where a is the acceleration, g is the acceleration due to gravity at the place and Θ is the angle between the plane and the horizontal.)But if the slope is irregular or not uniform, the acceleration will vary.Speed:Since the ball has an acceleration, it's speed will change. The speed of a ball rolling down a sloped plane will keep on increasing.
Yes, a boulder rolling down a hill has mass and velocity. Therefore, it has momentum because p = mv (momentum = mass x velocity).
Yes, if it is rolling at a constant speed it has potential energy.
A ball rolling at a constant speed at the same rate of speed on a still surface.
Net forces. Consider a velocity - time graph for a person free falling from a plane. Initially, on leaving the plane, the only force is due to the mass of the person under the effect of gravity, f = m * g (newtons) and effectively gives an initial acceleration of 1 g (about 10 ((m/s)/s)). As soon as you are in motion however, air resistance will provide an opposing force (proportional to the square of the velocity), reducing the net force providing acceleration, so your velocity increase per second, will be diminished the faster you go. Eventually the air resistance will match the force due to gravity at what is known as terminal velocity, where the net force is 0 and no further acceleration takes place. : Force down (constant) = mass * acceleration due to gravity. Force up (varies with velocity) = velocity2 * drag coefficient. The same reasoning can be applied to accelerating vehicles, except there are additional forces against due to rolling resistance. an example graph form is v = 10t - t2, t from 0 to 5