You have 22 dimes and 11 pennies.
The coins in the store's cash register total $12.50. The cash register contains only nickels, dimes, and quarters. There are twice as many dimes as nickels. There are also twice as many quarters as dimes. How many quarters are in the cash register?
12 quarters and 6 dimes 2(.25x) + .10x = 3.60 50x + 10x = 360 60x = 360 x = 6
7 quarters 2 dimes 4 nickels
16 nickels, 8 dimes, 4 quarters. 25+25+25+25+10+10+10+10+10+10+10+10+5+5+5+5+5+5+5+5+5+5+5+5+5+5+5+5= 260
Assuming you did not add the pennies, but merely doubled the amount, on the 365th day, you would have 2364 pennies = about 3.76 x 10107 dollars, which is an implausibly large sum of money. The gross domestic product of the entire Earth is only about 80 to 90 x 1012 dollars. 10107 is trillions of times the total number of electrons in the universe. If you kept each group of pennies as you doubled, you would have (2365 - 1) pennies, or almost exactly twice as much money.
You have 22 dimes and 11 pennies.
apples
The X.X1 at the end of the number implies that there could be 1, 11, 21, 31, etc. pennies. Now, we could go through and test the instances. .01 means that there is 1 penny. Therefore, there are 2 dimes to make .31, which does not work. .11 means that there are 11 pennies. Therefore, 22 dimes are required, which make $2.31. This works, so there are 22 dimes.
There are fifteen (15) nickels.
The coins in the store's cash register total $12.50. The cash register contains only nickels, dimes, and quarters. There are twice as many dimes as nickels. There are also twice as many quarters as dimes. How many quarters are in the cash register?
12 quarters 6 dimes
10 dimes 5 quarters
You need to define variables for the different types of coins, write the corresponding equations, then solve them. One equation for each fact. Here are the equations:5N + 10D + 25Q = 1250 D = 2N Q = 2D
Helen has twice as many dimes as nickels and five more quarters than nickels the value of her coins is 4.75 how many dimes does she have?
12 quarters and 6 dimes 2(.25x) + .10x = 3.60 50x + 10x = 360 60x = 360 x = 6
7 quarters 2 dimes 4 nickels
Twelve. Here is how: Using cents rather than decimal dollars: 5n + 10d + 25q = 640 Express the numbers of nickels and quarters in terms of the number of dimes: # of nickels = twice the # of dimes ==> n = 2d # of quarters = 5 less than the # of dimes ==> q = d-5 Substitute for n & q in original equation: 5(2d) + 10d + 25(d-5) = 640 45d - 125 = 640 45d = 765 d = 17 ==> 170 = $1.70 n = 34 ==> 170 = $1.70 q = 12 ==> 300 = $3.00 . . . . . . . . . Total = $6.40