A stone that falls from a ledge and takes 8 second to hit the ground travels a distance of 313.6 meters. You can find this answer by substituting 8 seconds for time in the physics formula d = 1/2 x acceleration x (t squared), where d = distance, acceleration is given as a =9.8 meters/second squared, and t squared is time in seconds.
92.2m/s
H = 1/2 g T2 = (4.9) (64) = 313.6 meters.H = 1/2g T2 = (4.9) x (8)2 = 4.9 x 64 = 313.6 meters
The approximate gravitational acceleration on Earth is 9.8 meters per second. Neglecting air friction is s equals 4.9 times 16 squared. S is equal to 1254.4 meters which is equal to 4100 feet.
A 92.2 m/s V = (4 m/s) + (9.8 m/s²) (9 s) V = 92.2 m/s
We have to trust the equation you give us, telling us that the acceleration of gravity is 9.8,the tossing speed is 20 straight up, and the stone leaves your hand from 10 aboveground.If all of that is true, then H = -4.9 t2 + 20t + 10, and when the stone hits the ground,-4.9 t2 + 20t + 10 = 0Multiply both sides of the equation by -1 :4.9 t2 - 20t - 10 = 0We're not going to be able to factor that ugly thing,so we have to use the quadratic equation:t = [ 20 +/- sqrt(400 + 196) ] / 9.8 = ( 20 +/- 24.413) / 9.8I get 4.532 seconds (rounded)
92.2m/s
H = 1/2 g T2 = (4.9) (64) = 313.6 meters.H = 1/2g T2 = (4.9) x (8)2 = 4.9 x 64 = 313.6 meters
H = 1/2 g T2 = (4.9) (64) = 313.6 meters.H = 1/2g T2 = (4.9) x (8)2 = 4.9 x 64 = 313.6 meters
The approximate gravitational acceleration on Earth is 9.8 meters per second. Neglecting air friction is s equals 4.9 times 16 squared. S is equal to 1254.4 meters which is equal to 4100 feet.
A 92.2 m/s V = (4 m/s) + (9.8 m/s²) (9 s) V = 92.2 m/s
If a stone falls from a ledge and takes 16 seconds to hit bottom, then the bottom is 1413 meters away. This assumes acceleration due to gravity of 9.81 meters per second squared, an initial velocity of zero, and no friction due to air resistance. Air resistance will decrease the distance.x = 1/2 at2 + v0t + x0
On Earth gravity equals 9.8 m/s^2. If you multiply that by 8 seconds you get: 78.4m/s
D. 36 m/s
The time required for a stone to fall from a given height can be calculated mathematically. Time equals the square root of two times the distance divided by force of gravity. Time is in seconds, distance in meters, and the force of gravity on Earth is 9.8 meters/second ^2.
490 meters
A stone falls freely from rest The total distance covered by it in the last second of its motion equals the distance covered by it in the first three seconds How long does the stone remain in air?
78.4 m/s