Q: A ten digit number in which 1st digit indicates the number of 0s and 2nd digit indicates the number of 1's and so on the 10th digit indicates the number of 9's what is that 10 digit number?

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Your 10th birthday is your first two-digit birthday. In the same way, your 100th birthday is your first three-digit birthday.

There are 17 such numbers.

For the group of 3 digit numbers : Any number from 1-9 can be the 1st digit, any number from 0-9 can be the 2nd digit, the 3rd digit can only be one number that matches the 1st digit. The number of possibilities is thus, 9 x 10 x 1 = 90. For the group of 4 digits : Any number from 1-9 can be the 1st digit, any number from 0-9 can be the second digit, the 3rd digit can only be the one number that matches the 2nd number, and the 4th digit can only be the one number that matches the 1st digit. Number of possibilities is 9 x 10 x 1 x 1 = 90. Giving a total of 180 palindromic numbers between 100 and 10000.

Well I believe that when you divide the number 1st you have to see if the number will go in to the three digit number and if don't then see if another can go into that one

1349.

/*this v'll work to obtain sum of 1st and last number of any number */#includeint main(){int num,sum=0,i,fd,ld;printf("enter the number);scanf("%d",&num);ld=n%10; //will get the last digitwhile(num!=0){fd=n;n/10; //to get the 1st digit}sum=fd+ld; //add 1st n last digitprintf("\n sum of 1st n last digit is %d",sum)}

// this v'll work to obtain sum of 1st and last number of any number#includeint main(){int num,sum=0,i,fd,ld;printf("enter the number);scanf("%d",&num);ld=n%10; //will get the last digitwhile(num!=0){fd=n;n/10; //to get the 1st digit}sum=fd+ld; //add 1st n last digitprintf("\n sum of 1st n last digit is %d",sum)}

29256

73 84 __________ 292 (multiply 1st number by the unit position digit of 2nd number) 5840 (multiply 1st number by the ten position digit of 2nd number, hence __________ force a zero in the unit position) 6132 __________

It is the 1st digit 7 that is in the thousands place

The 1st digit which has a value of 500

1st = 12 then 16 20 24 28 32 36 40 44 so 10th = 48

3942

To solve this question, two cases must be considered:Case 1: The three-digit even number ends with 0.If the three-digit number ends with 0, then the number must be even. After the digit 0 is used, six digits remain. After any one of these six digits is chosen to be the first digit, five digits remain. To complete the number, any of the five remaining digits could be chosen to be the second digit of the number.___6___ * ___5___ * ___1___ = 30 three-digit even numbers ending in 0.1st digit-------2nd digit----3rddigit (0)Case 2: The three-digit even number does not end with 0.If the three-digit number does not end with 0, it can end with 2 or 4. Therefore, there are two possibilities for the third digit. The first digit could be any of the remaining digits, EXCEPT 0: if 0 were the first digit, it would not be a three-digit number. Therefore, there would be five possible digits for the first digit. 0 could be used as the second digit, along with the four remaining digits that were not previously used.___5___ * ___5___ * ___2___ = 50 three-digit even numbers not ending in 0.1st digit-------2nd digit-----3rddigit (0)The total number of three-digit even numbers is 80, since 30 three-digit even numbers ending in 0 plus 50 three-digit even numbers not ending in 0 equals 80.

the last number of your CASE NUMBER (the one with letters) will determine the day your card refills it can be the 1st to the 10th of the month

12689 14689 12489

It is the first non-zero digit, starting from the left. It can be before or after the decimal point.

new 1st/10th/20th sub

The 10000th digit of pi, counting the starting 3 as the 1st digit is 7 but the 10000th digit AFTER the decimal point is 8.

Let's assume there are 5 total digits, although that would have been handy information to include. All we can deduce from the available information is 4 of the digits. 318_2 There are ten possible digits for the 4th number, leaving 10 possible numbers.

You have 5 choices for the 1st digit of the number. 4 choices for the 2nd digit and 3 choices for the 3rd and final digit. This means that there are 5 x 4 x 3 = 60 3-digit numbers that can be made from 5 different digits subject to each digit only being used once.

The first digit can be any one of nine (all except zero). For each of those . . .The second digit can be any one of ten.Total possibilities for the first two digits = 9 x 10 = 90.Since the 4-digit number is a palindrome, the 3rd and 4th digits are determinedby the 1st and 2nd ones.So the total number of 4-digit palindromes is the same as the number of possibilitiesfor the first 2 digits = 90 .

It was made in the 1st year of production, 1894!

0 - There are no 0s in pi 1 - 2nd digit 2 - 7th digit 3 - 1st digit 4 - 3rd digit 5 - 5th digit 6 - 8th digit 7 - 14th digit 8 - 12th digit 9 - 6th digit

Engine Identification. The vehicle identification number (VIN) is located on the left side rear of the engine block and is typically a 9 digit number stamped or laser-etched onto the engine at the assembly plant. - The 1st digit identifies the division. - The 2nd digit identifies the model year. - The 3rd digit identifies the assembly plant. - The 4th through 9th digits are the last 6 digits of the 17 digit VIN found on the body. According to my Chevy dealer, the engine number can be derived from the VIN as follows: - The 3rd digit of your VIN represents the division code. - The 10th digit of your VIN represents the model year. - The 11th digit of your VIN represents the plant code. - The 12th through 17th digits of your VIN represent the sequence number (the last 6 digits of the engine vin). Also according to the dealer, the only way to actually see the VIN on an engine is to actually remove. Apparently the clearances are so tight. This information about the engine VIN also applies to Chevy Tahoes.