A water storage tank measures 2m x 1.5m x 2m and contains water to a depth of 1.6m. Given that the pressure exerted by 1m3 of water is 9.81kNm2 how to calculations?

Answer 1

Well, honey, first calculate the volume of water in the tank by multiplying the dimensions. Then, multiply the volume by the pressure exerted by 1m3 of water to get the total pressure. So, for this tank, it would be 2m x 1.5m x 1.6m x 9.81kNm2. Don't forget your units, sweetie!

Answer 2

To calculate the pressure exerted by the water in the tank, you first need to find the volume of water in the tank. The volume can be calculated by multiplying the length, width, and depth of the water (2m x 1.5m x 1.6m = 4.8m³). Then, you can multiply the volume by the pressure exerted by 1m³ of water (4.8m³ x 9.81kNm² = 47.088kN). Therefore, the pressure exerted by the water in the tank is 47.088kNm².

Answer 3

Oh, dude, it's like this - you take the height of the water in the tank, which is 1.6m, and multiply it by the density of water, which is 1000 kg/m³, and then multiply that by the acceleration due to gravity, which is 9.81 m/s². That gives you the pressure at the bottom of the tank in pascals. Then, you can convert that to kilonewtons per square meter by dividing by 1000. And voilà, you've got your pressure in kNm². Easy peasy, right?

Answer 4

A water storage tank measures 2m x 1.5m x 2m and contains water to a depth of 1.6m. Given that the pressure exerted by 1m3 of water is 9.81kNm2 how to calculations?