If cutting off 5 inches left 4 inches, then the original length of one piece was 9 inches. The other piece was also 9 inches. Therfore the original piece of construction paper was 18 inches
169 square inches. Folding the square in half leaves 2 edges of the original side length and two of half the side length. Therefore: perimeter = side + 1/2 side + side + 1/2 side = 3 sides ⇒ 3 sides = 39 inches ⇒ 1 side = 39 inches ÷ 3 = 13 inches ⇒ area_original_square = 13 inches x 13 inches = 169 square inches.
A rectangle and a triangle have equal areas. The length of the rectangle is 12 inches, and its width is 8 inches. If the base of the triangle is 32 inches, what is the length, in inches, of the altitude drawn to the base? WRONG WRONG WRONG NO NO NO ::"::":""::":"""::"":":""::::::::::::: ::"::": ::":: :: ::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::"
1,200 mm = 3 feet 11.2 inches
My math book is about 11 inches in length and 9 inches wide.
Area = Length * Width = 12*7 = 84 square inches.
9-11 inches long
12 inches
You need to specify the original units. Do you want to convert 850 metres to feet/inches? 850 light-years?
34 3/4 inches
169 square inches. Folding the square in half leaves 2 edges of the original side length and two of half the side length. Therefore: perimeter = side + 1/2 side + side + 1/2 side = 3 sides ⇒ 3 sides = 39 inches ⇒ 1 side = 39 inches ÷ 3 = 13 inches ⇒ area_original_square = 13 inches x 13 inches = 169 square inches.
20 inches
LENGTH and WIDTH
Inches are used for measuring length. Tailors measure inches for the length of a man's trousers.
The length is 7 inches and the width is 5 inches for a envelope
length
It depends on the length of the original bananna. If the bananna was 12 inches to start then Adams's piece is six inches, Scott's is four inches and Tony's is two inches. they would be the same length if cut the long way
Width = 9 inches Length = 30 inches