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Andy is twice as old as kate In 6 years their ages will total how old is each now?
Wiki User
∙ 15y ago
You forgot to enter the total age. But that's OK. We can solve this puzzle in general. Let A = Andy's age now. Let K = Kate's age now. Then your problem statement can be written A = 2K (A+6) + (K+6) = T , where T is the total of the ages in 6 years. Then, substituting 2K for A in rthe second equation, we have 2K+6 + K+6 = T, or 3K = T-12 Here is a table of solutions for various T ("Total age in six years"): T A K ---- 15 2 1 18 4 2 21 6 3 24 8 4 ... 48 24 12 51 26 13 etc.
Wiki User
∙ 15y ago
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John is twice as old as his brother Four years ago he was four times as old as his brother Find their present ages?
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The sum of present ages of a and b is 42 years the ratio of their ages after 5 years will be 15 is to 11 then what is the present age of b?
Total ages at present = 42 Total ages in 10 years = 52 Fractions then 15/26 x 52 and 11/26 x 52, ie 30 and 22 so ages now 25 and 17
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32
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